Python实现栈
栈的操作
- Stack() 创建一个新的空栈
- push(item) 添加一个新的元素item到栈顶
- pop() 弹出栈顶元素
- peek() 返回栈顶元素
- is_empty() 判断栈是否为空
- size() 返回栈的元素个数
class Stack: def __init__(self): self.items = [] def isEmpty(self): return self.items == [] def push(self, item): self.items.append(item) def pop(self): return self.items.pop() def peek(self): return self.items[len(self.items)-1] def size(self): return len(self.items)
from pythonds.basic.stack import Stack s = Stack() print(s.isEmpty()) s.push(4) s.push('dog') print(s.peek()) s.push(True) print(s.size()) print(s.isEmpty()) s.push(8.4) print(s.pop()) print(s.pop()) print(s.size())
用栈处理简单括号匹配问题
from pythonds.basic.stack import Stack def parChecker(symbolString): s = Stack() balanced = True index = 0 while index < len(symbolString) and balanced: symbol = symbolString[index] if symbol == "(": s.push(symbol) else: if s.isEmpty(): balanced = False else: s.pop() index = index + 1 if balanced and s.isEmpty(): return True else: return False print(parChecker('((()))')) print(parChecker('(()'))
多括号匹配问题
from pythonds.basic.stack import Stack def parChecker(symbolString): s = Stack() balanced = True index = 0 while index < len(symbolString) and balanced: symbol = symbolString[index] if symbol in "([{": s.push(symbol) else: if s.isEmpty(): balanced = False else: top = s.pop() if not matches(top,symbol): balanced = False index = index + 1 if balanced and s.isEmpty(): return True else: return False def matches(open,close): opens = "([{" closers = ")]}" return opens.index(open) == closers.index(close) print(parChecker('{{([][])}()}')) print(parChecker('[{()]'))
进制转换
from pythonds.basic.stack import Stack def baseConverter(decNumber,base): digits = "0123456789ABCDEF" remstack = Stack() while decNumber > 0: rem = decNumber % base remstack.push(rem) decNumber = decNumber // base newString = "" while not remstack.isEmpty(): newString = newString + digits[remstack.pop()] return newString print(baseConverter(25,2)) print(baseConverter(25,16))