Leetcode: Reverse Words in a String II
Given an input string, reverse the string word by word. A word is defined as a sequence of non-space characters. The input string does not contain leading or trailing spaces and the words are always separated by a single space. For example, Given s = "the sky is blue", return "blue is sky the". Could you do it in-place without allocating extra space?
这道题要求in-place做法,不能使用extra space, 那么,做法跟Rotate Array那道题非常相似
(1)reverse the whole array
(2)reverse each subarray seperated by ' '
注意不要忘了reverse最后一个word
1 public void reverseWords(char[] s) { 2 // Three step to reverse 3 // 1, reverse the whole sentence 4 reverse(s, 0, s.length - 1); 5 // 2, reverse each word 6 int start = 0; 7 int end = -1; 8 for (int i = 0; i < s.length; i++) { 9 if (s[i] == ' ') { 10 reverse(s, start, i - 1); 11 start = i + 1; 12 } 13 } 14 // 3, reverse the last word, if there is only one word this will solve the corner case 15 reverse(s, start, s.length - 1); 16 } 17 18 public void reverse(char[] s, int start, int end) { 19 while (start < end) { 20 char temp = s[start]; 21 s[start] = s[end]; 22 s[end] = temp; 23 start++; 24 end--; 25 } 26 }