IDEA下——Spring入门程序
- 创建一个Maven的项目,我的项目结构如下:
- 在pom文件里写下需要导入的依赖:
<?xml version="1.0" encoding="UTF-8"?>
<project xmlns="http://maven.apache.org/POM/4.0.0"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/POM/4.0.0
http://maven.apache.org/xsd/maven-4.0.0.xsd">
<modelVersion>4.0.0</modelVersion>
<groupId>com.abc</groupId>
<artifactId>01-first(Spring)</artifactId>
<version>1.0-SNAPSHOT</version>
<build>
<plugins>
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-compiler-plugin</artifactId>
<configuration>
<source>6</source>
<target>6</target>
</configuration>
</plugin>
</plugins>
</build>
<properties>
<project.build.sourceEncoding>UTF-8</project.build.sourceEncoding>
<maven.compiler.source>10</maven.compiler.source>
<maven.compiler.target>10</maven.compiler.target>
<spring.version>5.1.0.RELEASE</spring.version>
</properties>
<dependencies>
<dependency>
<groupId>org.springframework</groupId>
<artifactId>spring-beans</artifactId>
<version>${spring.version}</version>
</dependency>
<dependency>
<groupId>org.springframework</groupId>
<artifactId>spring-core</artifactId>
<version>${spring.version}</version>
</dependency>
<dependency>
<groupId>org.springframework</groupId>
<artifactId>spring-context</artifactId>
<version>${spring.version}</version>
</dependency>
<dependency>
<groupId>org.springframework</groupId>
<artifactId>spring-expression</artifactId>
<version>${spring.version}</version>
</dependency>
<dependency>
<groupId>org.springframework</groupId>
<artifactId>spring-jcl</artifactId>
<version>${spring.version}</version>
</dependency>
<dependency>
<groupId>junit</groupId>
<artifactId>junit</artifactId>
<version>4.12</version>
<scope>test</scope>
</dependency>
</dependencies>
<build>
<plugins>
<plugin>
<artifactId>maven-compiler-plugin</artifactId>
<configuration>
<source>1.10</source>
<target>1.10</target>
</configuration>
</plugin>
</plugins>
</build>
</project>
-
在Java文件夹下新建package,在package包下新建接口及其实现类
接口:public interface SomeService { void doSome(); }
实现类:
public class SomeServiceImpl implements SomeService { public SomeServiceImpl() { System.out.println("创建SomeServiceImpl对象"); } @Override public void doSome() { System.out.println("执行SomeServiceImpl里的doSome()方法"); } }
-
在resources目录下新建
applicationContext.xml
文件
- 我们需要在spring容器的配置文件中进行注册该Bean
- spring使用的配置文件为xml文件,当然需要引入约束文件,一般将spring的配置文件命名为applicationContext.xml
<?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd"> <!--注册Servcie其造价于如下代码: SomeServiceImpl someService = new SomeServiceImpl(); 其底层是通过反射机制创建的someService对象 Object someService = Class.forName("com.abc.service.SomeServiceImpl").newInstance();--> <bean id="someService" class="com.abc.service.SomeServiceImpl"/> </beans>
* spring的根元素是benas显然是注册Bean,子标签是Bean
* 注册:`<bean id="someService" class="com.abc.service.SomeServiceImpl"/>`
* id属性为了唯一确定一个对象,class属性里边应写类全名
5. 注册完毕后我们要在测试类中获取spring容器,而获取Spring容器有两种方式。
package com.abc.service;
import org.junit.Test;
import org.springframework.context.ApplicationContext;
import org.springframework.context.support.ClassPathXmlApplicationContext;
import org.springframework.context.support.FileSystemXmlApplicationContext;
public class SomeServiceImplTTest {
// spring容器获取的两种方式
@Test
public void test01(){
//在类路径下加载Spring配置文件
ApplicationContext ac = new ClassPathXmlApplicationContext("applicationContext.xml");
//在当前目录的根下加载该配置文件,路径应为文件实际存放的目录
ApplicationContext ac2 = new FileSystemXmlApplicationContext
("D:\\IDEA-workspace\\01-first(Spring)\\src\\main\\resources\\applicationContext.xml");
System.out.println(ac2);
}
@Test
public void test02() {
// 加载Spring配置文件,创建Spring容器对象
ApplicationContext ac = new ClassPathXmlApplicationContext("applicationContext.xml");
//调用spring容器的getBean方法获取carImpl,方法参数为bean的id
SomeService service = (SomeService) ac.getBean("SomeService");
service.doSome();
}
}
Spring入门程序到此就结束了