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摘要: Race to 1Time Limit:10000MSMemory Limit:Unknown64bit IO Format:%lld & %llu[Submit] [Go Back] [Status]DescriptionBRace to 1Input:Standard InputOutput:Standard OutputDilu have learned a new thing about integers, which is - any positive integer greater than 1 can be divided by at least one prime nu 阅读全文
posted @ 2014-04-05 00:26 ERKE 阅读(168) 评论(0) 推荐(0) 编辑
摘要: 不要62Time Limit: 1000/1000 MS (Java/Others)Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 16975Accepted Submission(s): 5566Problem Description杭州人称那些傻乎乎粘嗒嗒的人为62(音:laoer)。杭州交通管理局经常会扩充一些的士车牌照,新近出来一个好消息,以后上牌照,不再含有不吉利的数字了,这样一来,就可以消除个别的士司机和乘客的心理障碍,更安全地服务大众。不吉利的数字为所有含有4或62的号码。例如:62315 73418 8 阅读全文
posted @ 2014-04-02 13:04 ERKE 阅读(254) 评论(0) 推荐(0) 编辑
摘要: Kia's CalculationTime Limit: 2000/1000 MS (Java/Others)Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1367Accepted Submission(s): 327Problem DescriptionDoctor Ghee is teaching Kia how to calculate the sum of two integers. But Kia is so careless and alway forget to carry a number w 阅读全文
posted @ 2014-04-01 13:17 ERKE 阅读(164) 评论(0) 推荐(0) 编辑
摘要: The Moving PointsTime Limit: 6000/3000 MS (Java/Others)Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 964Accepted Submission(s): 393Problem DescriptionThere are N points in total. Every point moves in certain direction and certain speed. We want to know at what time that the largest d 阅读全文
posted @ 2014-03-31 23:13 ERKE 阅读(212) 评论(0) 推荐(0) 编辑
摘要: Naive and Silly MugglesTime Limit: 2000/1000 MS (Java/Others)Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 452Accepted Submission(s): 307Problem DescriptionThree wizards are doing a experiment. To avoid from bothering, a special magic is set around them. The magic forms a circle, whi 阅读全文
posted @ 2014-03-31 22:24 ERKE 阅读(173) 评论(0) 推荐(0) 编辑
摘要: Problem 2144 Shooting GameAccept: 99Submit: 465Time Limit: 1000 mSecMemory Limit : 32768 KBProblem DescriptionFat brother and Maze are playing a kind of special (hentai) game in the playground. (Maybe it’s the OOXX game which decrypted in the last problem, who knows.) But as they don’t like using re 阅读全文
posted @ 2014-03-31 13:35 ERKE 阅读(250) 评论(0) 推荐(0) 编辑
摘要: 1、本原勾股数:概念:一个三元组(a,b,c),其中a,b,c没有公因数而且满足:a^2+b^2=c^2首先,这种本原勾股数的个数是无限的,而且构造的条件满足:a=s*t,b=(s^2-t^2)/2,c=(s^2+t^2)/2其中s>t>=1是任意没有公因数的奇数!由以上概念就可以导出任意一个本原勾股数组。2、素数计数(素数定理)令π(x)为1到x中素数的个数19世纪最高的数论成就就是以下这个玩意儿:lim(x->∞){π(x)/(x/ln(x))}=1数论最高成就,最高成就!!!有木有!!!3、哥德巴赫猜想(1+1)一个大偶数(>=4)必然可以拆分为两个素数的和,虽然 阅读全文
posted @ 2014-03-28 22:49 ERKE 阅读(237) 评论(0) 推荐(0) 编辑
摘要: 1.burnside定理,polya计数法 这个大家可以看brudildi的《组合数学》,那本书的这一章写的很详细也很容易理解。最好能完全看懂了,理解了再去做题,不要只记个公式。 *简单题:(直接用套公式就可以了) pku2409 Let it Bead http://acm.pku.edu.cn/JudgeOnline/problem?id=2409 pku2154 Color http://acm.pku.edu.cn/JudgeOnline/problem?id=2409 pku1286 Necklace of Beads ... 阅读全文
posted @ 2014-03-28 22:32 ERKE 阅读(186) 评论(0) 推荐(0) 编辑
摘要: Eddy's爱好Time Limit: 3000/1000 MS (Java/Others)Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1266Accepted Submission(s): 541Problem DescriptionIgnatius 喜欢收集蝴蝶标本和邮票,但是Eddy的爱好很特别,他对数字比较感兴趣,他曾经一度沉迷于素数,而现在他对于一些新的特殊数比较有兴趣。这些特殊数是这样的:这些数都能表示成M^K,M和K是正整数且K>1。正当他再度沉迷的时候,他发现不知道什么时候才能知道这样 阅读全文
posted @ 2014-03-28 20:45 ERKE 阅读(162) 评论(0) 推荐(0) 编辑
摘要: 本原串Time Limit: 1000/1000 MS (Java/Others)Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 580Accepted Submission(s): 202Problem Description由0和1组成的串中,不能表示为由几个相同的较小的串连接成的串,称为本原串,有多少个长为n(n 2 #include 3 #include 4 #include 5 using namespace std; 6 #define mod 2008 7 #define ll int 8 int ... 阅读全文
posted @ 2014-03-25 23:12 ERKE 阅读(180) 评论(0) 推荐(0) 编辑
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