摘要: SumTime Limit: 2000/1000 MS (Java/Others)Memory Limit: 131072/131072 K (Java/Others) Total Submission(s): 127Accepted Submission(s): 60 Problem DescriptionSample Input2Sample Output2解题思路:很容易看得出,这是个组合数学的插板问题,答案为2^(n-1);由于n特别大,则(2^(n-1))%1000000007=(2^((n-1)%1000000006))%1000000007;因为1000000007为素数,设为p 阅读全文
posted @ 2013-08-22 19:03 ERKE 阅读(395) 评论(0) 推荐(0) 编辑