String的hashCode 和equals 区别

  网上找到特么一段话:

Java对于equals方法和hashCode方法是这样规定的: 
  1、如果两个对象相等,那么它们的hashCode值一定要相等; 
  2、如果两个对象的hashCode相等,它们并不一定相等
PS:相等说的是equals方法。

   那么这2个方法是什么来的??

 

   先祭出源码。

  equals源码

    /**
     * Compares this string to the specified object.  The result is {@code
     * true} if and only if the argument is not {@code null} and is a {@code
     * String} object that represents the same sequence of characters as this
     * object.
     *
     * @param  anObject
     *         The object to compare this {@code String} against
     *
     * @return  {@code true} if the given object represents a {@code String}
     *          equivalent to this string, {@code false} otherwise
     *
     * @see  #compareTo(String)
     * @see  #equalsIgnoreCase(String)
     */
    public boolean equals(Object anObject) {
    if (this == anObject) {
        return true;
    }
    if (anObject instanceof String) {
        String anotherString = (String)anObject;
        int n = count;
        if (n == anotherString.count) {
        char v1[] = value;
        char v2[] = anotherString.value;
        int i = offset;
        int j = anotherString.offset;
        while (n-- != 0) {
            if (v1[i++] != v2[j++])
            return false;
        }
        return true;
        }
    }
    return false;
    }

   equals方法, 关键点就是把字符串当成字符数组(char[]),然后两个相同长度的字符数组每个相同下标的字符进行比较。

 

  hashCode源码

    /**
     * Returns a hash code for this string. The hash code for a
     * <code>String</code> object is computed as
     * <blockquote><pre>
     * s[0]*31^(n-1) + s[1]*31^(n-2) + ... + s[n-1]
     * </pre></blockquote>
     * using <code>int</code> arithmetic, where <code>s[i]</code> is the
     * <i>i</i>th character of the string, <code>n</code> is the length of
     * the string, and <code>^</code> indicates exponentiation.
     * (The hash value of the empty string is zero.)
     *
     * @return  a hash code value for this object.
     */
    public int hashCode() {
    int h = hash;
        int len = count;
    if (h == 0 && len > 0) {
        int off = offset;
        char val[] = value;

            for (int i = 0; i < len; i++) {
                h = 31*h + val[off++];
            }
            hash = h;
        }
        return h;
    }

  hashCode是对字符串每一个字符做一个简单“编码”后,累加值。并不严格规定每一个字符相等。

  

 

posted on 2015-08-07 19:56  Emmerich.Luang  阅读(286)  评论(0编辑  收藏  举报

导航