Codeforces 839A Arya and Bran【暴力】

A. Arya and Bran

time limit per test:1 second
memory limit per test:256 megabytes
input:standard input
output:standard output

Bran and his older sister Arya are from the same house. Bran like candies so much, so Arya is going to give him some Candies.

At first, Arya and Bran have 0 Candies. There are n days, at the i-th day, Arya finds ai candies in a box, that is given by the Many-Faced God. Every day she can give Bran at most 8 of her candies. If she don't give him the candies at the same day, they are saved for her and she can give them to him later.

Your task is to find the minimum number of days Arya needs to give Bran k candies before the end of the n-th day. Formally, you need to output the minimum day index to the end of which k candies will be given out (the days are indexed from 1 to n).

Print -1 if she can't give him k candies during n given days.

Input

The first line contains two integers n and k (1 ≤ n ≤ 100, 1 ≤ k ≤ 10000).

The second line contains n integers a1, a2, a3, ..., an (1 ≤ ai ≤ 100).

Output

If it is impossible for Arya to give Bran k candies within n days, print -1.

Otherwise print a single integer — the minimum number of days Arya needs to give Bran k candies before the end of the n-th day.

Examples
Input
2 3
1 2
Output
2
Input
3 17
10 10 10
Output
3
Input
1 9
10
Output
-1
Note

In the first sample, Arya can give Bran 3 candies in 2 days.

In the second sample, Arya can give Bran 17 candies in 3 days, because she can give him at most 8 candies per day.

In the third sample, Arya can't give Bran 9 candies, because she can give him at most 8 candies per day and she must give him the candies within 1 day.

题目链接:http://codeforces.com/contest/839/problem/A

分析:题意大概是第n天结束之前需要给予Bran k糖果的最少天数,暴力即可,不过这题目题意确实有点迷就是了!

下面给出AC代码:

复制代码
 1 #include <bits/stdc++.h>
 2 using namespace std;
 3 int main()
 4 {
 5     int n,m;
 6     cin>>n>>m;
 7     int ans=0;
 8     for(int i=1;i<=n;i++)
 9     {
10         int x;
11         cin>>x;
12         ans+=x;
13         m-=min(ans,8);
14         ans-=min(ans,8);
15         if(m<=0)
16             return !printf("%d\n",i);
17     }
18     return !printf("-1\n");
19 }
复制代码

 

posted @   Angel_Kitty  阅读(360)  评论(0编辑  收藏  举报
编辑推荐:
· 如何编写易于单元测试的代码
· 10年+ .NET Coder 心语,封装的思维:从隐藏、稳定开始理解其本质意义
· .NET Core 中如何实现缓存的预热?
· 从 HTTP 原因短语缺失研究 HTTP/2 和 HTTP/3 的设计差异
· AI与.NET技术实操系列:向量存储与相似性搜索在 .NET 中的实现
阅读排行:
· 周边上新:园子的第一款马克杯温暖上架
· Open-Sora 2.0 重磅开源!
· 分享 3 个 .NET 开源的文件压缩处理库,助力快速实现文件压缩解压功能!
· Ollama——大语言模型本地部署的极速利器
· [AI/GPT/综述] AI Agent的设计模式综述
点击右上角即可分享
微信分享提示
哥伦布
14°
14:09发布
哥伦布
14:09发布
14°
大雨
南风
3级
空气质量
相对湿度
93%
今天
中雨
14°/19°
周日
中雨
5°/19°
周一
1°/11°