随笔分类 - online judge：Uva
摘要：题目链接：uva 1030 - Image Is Everything 题目大意：有一个最大为n*n*n的立方体的一个不规整立体，由若干个1*1*1的小正方体构成（每一个小正方体被涂成不同的颜色），给出n，然后是该立体的前、左、后、右、上和下的视图，然后判断该立体的最大体积是多少。 解题思路：首先先
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摘要：题目链接：http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&problem=1822 题意：有很多只蚂蚁在一条直线上，每个蚂蚁移动速度都是1，并且有一个初始方向。并且当相邻两个
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摘要：UVa 10382 - Watering Grass n sprinklers are installed in a horizontal strip of grass l meters long and w meters wide. Each sprinkler is installed at t
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摘要：UVA11039-Building designing Time limit: 3.000 seconds An architect wants to design a very high building. The building will consist of some floors, and
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摘要：UVA11636-Hello World! Time limit: 1.000 seconds When you first made the computer to print the sentence “Hello World!”, you felt so happy, not knowing h
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摘要：原题： Solve the equation: p*e-x + q*sin(x) + r*cos(x) + s*tan(x) + t*x2 + u = 0 where 0 <= x <= 1. Input Input consists of multiple test cases and termi
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摘要：题目链接：https://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&problem=2456 题意 输入两个整数a和b，输出从a到b（包含a和b）的平方数的个数。直到输入0 0时程序
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摘要：题目链接：uva 12050 - Palindrome Numbers 题意：求第n个回文串 思路：首先可以知道的是长度为k的回文串个数有9*10^(k-1),那么依次计算，得出n是长度为多少的串，然后就得到是长度为多少的第几个的回文串了，有个细节注意的是， n计算完后要-1！ 下面给出AC代码：
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摘要：题目链接：10339 - Watching Watches 题意：两个时钟，一个每天慢a秒，一个每天慢b秒，问两钟重新相遇的时刻 1圈有12 * 60 * 60秒，然后1圈 / abs(a - b),就可以求出多少天会相遇，然后就能求出A钟一共慢了多少秒，进而可以求出该时刻的时和分! 下面给出AC代
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摘要：Spreading the Wealth Problem A Communist regime is trying to redistribute wealth in a village. They have have decided to sit everyone around a circula
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摘要：Uva 11729 Commando War （简单贪心） There is a war and it doesn't look very promising for your country. Now it's time to act. You have a commando squad at y
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摘要：Problem C: The Dragon of Loowater Once upon a time, in the Kingdom of Loowater, a minor nuisance turned into a major problem. The shores of Rellau Cre
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