python 有关矩阵行列的存取 np.array
初始化
a = range(16)
a = np.array(a)
a = a.reshape(4,4)
- a
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[[ 0 1 2 3][ 4 5 6 7][ 8 9 10 11][12 13 14 15]]
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- 获取a的【0,1,4】行
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- b = a[ range( 2)+range( 3, 4),:]
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[[ 0 1 2 3][ 4 5 6 7][12 13 14 15]]
- 获取b的【0,1,4】列
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- c = b[:, range( 1 )+range(2 , 3)]
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[[ 0 2][ 4 6][12 14]]