LeetCode 1762. Buildings With an Ocean View
原题链接在这里:https://leetcode.com/problems/buildings-with-an-ocean-view/description/
题目:
There are n
buildings in a line. You are given an integer array heights
of size n
that represents the heights of the buildings in the line.
The ocean is to the right of the buildings. A building has an ocean view if the building can see the ocean without obstructions. Formally, a building has an ocean view if all the buildings to its right have a smaller height.
Return a list of indices (0-indexed) of buildings that have an ocean view, sorted in increasing order.
Example 1:
Input: heights = [4,2,3,1] Output: [0,2,3] Explanation: Building 1 (0-indexed) does not have an ocean view because building 2 is taller.
Example 2:
Input: heights = [4,3,2,1] Output: [0,1,2,3] Explanation: All the buildings have an ocean view.
Example 3:
Input: heights = [1,3,2,4] Output: [3] Explanation: Only building 3 has an ocean view.
Constraints:
1 <= heights.length <= 105
1 <= heights[i] <= 109
题解:
Traverse from right to left.
Whenever encoutner a bigger value, we find an ocean view and update the maximum.
Time Complexity: O(n). n = heights.length.
Space: O(n).
AC Java:
1 class Solution { 2 public int[] findBuildings(int[] heights) { 3 List<Integer> res = new ArrayList<>(); 4 int n = heights.length; 5 int max = 0; 6 for(int i = n - 1; i >= 0; i--){ 7 if(heights[i] > max){ 8 max = heights[i]; 9 res.add(i); 10 } 11 } 12 13 int[] resArr = new int[res.size()]; 14 for(int i = 0; i < res.size(); i++){ 15 resArr[res.size() - i - 1] = res.get(i); 16 } 17 18 return resArr; 19 } 20 }
AC Python:
1 class Solution: 2 def findBuildings(self, heights: List[int]) -> List[int]: 3 res = [] 4 maxHeight = float('-inf') 5 n = len(heights) 6 7 for i in range(n - 1, -1, -1): 8 if heights[i] > maxHeight: 9 maxHeight = heights[i] 10 res.append(i) 11 12 return res[::-1] 13