Girls' Day POJ 1677 模拟
Girls' Day
Time Limit: 1000MS | Memory Limit: 10000K | |
Total Submissions: 3145 | Accepted: 640 |
Description
On Girls' Day (Haven't heard about it? Well, you may ask the author for details...), we boys get together with girls in the class. On the occasion, every boy will make a wish for girls. Boys want to know about girls' responses to their wishes.
If a wish contains one or more girls' names, it is considered to be talking to them specifically. Otherwise it is talking to all the girls. A wish can simultaneously talk to several girls of course.
A girl would say 'oh' if the wish contains at most 9 words.
A girl would say 'xixi' if the wish contains at least 10 words and she hears the word 'beautiful', 'pretty' or 'lovely'.
A girl would say 'hehe' if the wish contains at least 10 words and she doesn't hear such words mentioned above.
It is confirmed that a wish will not contain all the girls? name.
If a wish contains one or more girls' names, it is considered to be talking to them specifically. Otherwise it is talking to all the girls. A wish can simultaneously talk to several girls of course.
A girl would say 'oh' if the wish contains at most 9 words.
A girl would say 'xixi' if the wish contains at least 10 words and she hears the word 'beautiful', 'pretty' or 'lovely'.
A girl would say 'hehe' if the wish contains at least 10 words and she doesn't hear such words mentioned above.
It is confirmed that a wish will not contain all the girls? name.
Input
The first line of the input contains two integers g and w (1 <= g <= 5, 1 <= w <= 30), the number of girls and the number of wishes respectively. The next g lines each contain a word in lowercase, representing the name of a girl. Then the next w lines each contain a string of letters and punctuations, namely the wish, which will contain at most 200 characters.
Each wish contains one or more sentences, and each sentence is terminated by a '!'. The first letter of each sentence is in uppercase, and other letters will be always in lowercase. No other characters apart from '!', spaces and letters will appear in the sentence. You may assume that each wish is correct in grammar.
Each wish contains one or more sentences, and each sentence is terminated by a '!'. The first letter of each sentence is in uppercase, and other letters will be always in lowercase. No other characters apart from '!', spaces and letters will appear in the sentence. You may assume that each wish is correct in grammar.
Output
You are required to give girls' response according to the input. For each wish, if it is talking to all the girls, print 'All', or otherwise print the list of girls that it is talking to (names are separated by a single space) in the order that they appear in the name list. Then print a semicolon followed by a space, and the response such as 'hehe' and 'xixi'.
Sample Input
5 5 answer baiqingr cedar juleo seven Happy girls day to all of you! Happy girls day to all of you!Wish you happy forever! Happy girls day for answer mm! Congratulations for cedar mm and seven mm!Wish you more and more beautiful hehe! Hello answer hello baiqingr hello juleo would you mind having dinner together!
Sample Output
All: oh All: hehe answer: oh cedar seven: xixi answer baiqingr juleo: hehe
Source
/* * Author: * Created Time: 2013/10/6 20:30:44 * File Name: A.cpp * solve: A.cpp */ #include<cstdio> #include<cstring> #include<cstdlib> #include<cmath> #include<algorithm> #include<string> #include<map> #include<stack> #include<set> #include<iostream> #include<vector> #include<queue> //ios_base::sync_with_stdio(false); //#pragma comment(linker, "/STACK:1024000000,1024000000") using namespace std; #define sz(v) ((int)(v).size()) #define rep(i, a, b) for (int i = (a); i < (b); ++i) #define repf(i, a, b) for (int i = (a); i <= (b); ++i) #define repd(i, a, b) for (int i = (a); i >= (b); --i) #define clr(x) memset(x,0,sizeof(x)) #define clrs( x , y ) memset(x,y,sizeof(x)) #define out(x) printf(#x" %d\n", x) #define sqr(x) ((x) * (x)) typedef long long LL; const int INF = 1000000000; const double eps = 1e-8; const int maxn = 100; int sgn(const double &x) { return (x > eps) - (x < -eps); } string name[maxn]; int used[maxn]; struct fuck { string name; int id; bool operator < (const fuck& f)const { return id < f.id; } }; vector<fuck> ans; char str[1000]; char temp[300]; string cmp[3] = {"beautiful","pretty","lovely"}; int main() { //freopen("in.txt","r",stdin); int n,w; scanf("%d%d",&n,&w); int Num = 0; rep(i,0,n) { string a; cin>>a; int tag = 0; rep(j,0,Num) if(name[j] == a) { tag = 1; break; } if(tag == 0) { name[Num] = a; Num++; } } getchar(); repf(i,1,w) { ans.clear(); int word = 0; int flag = 0; clr(used); gets(str); int len = strlen(str); str[len] = ' '; int cnt = 0; repf(j,0,len) { if(str[j] >= 'A' && str[j] <= 'Z') str[j] += 'a' - 'A'; if(str[j] == ' ' || str[j] == '!') { temp[cnt] = '\0'; string Name = temp; rep(k,0,3) if(cmp[k] == Name) flag = 1; rep(k,0,Num) { if(used[k]) continue; if(name[k] == Name) { used[k] = 1; ans.push_back((fuck){Name,k}); } } cnt = 0; continue; } temp[cnt] = str[j]; cnt++; } repf(j,0,len-1) { if(str[j] >= 'a' && str[j] <= 'z') { if(str[j+1] == ' ' || str[j+1] == '!') word++; } } int num = 0; rep(i,0,n) if(used[i]) num++; if(num == 0) printf("All: "); else { sort(ans.begin(),ans.end()); cout<<ans[0].name; rep(i,1,ans.size()) cout<<" "<<ans[i].name; cout<<": "; } if(word <= 9) { printf("oh\n"); continue; } if(word >= 10 && flag) { printf("xixi\n"); continue; } if(word >= 10 && !flag) { printf("hehe\n"); continue; } } return 0; }
posted on 2013-10-07 19:54 keep trying 阅读(247) 评论(0) 编辑 收藏 举报