摘要: var reg = new RegExp("(^|&)" + name + "=([^&]*)(&|$)", "i"); var r = window.location.search.substr(1).match(reg); if (r != null) return decodeURI(r[2] 阅读全文
posted @ 2016-04-16 16:26 CorderBob 阅读(180) 评论(0) 推荐(0) 编辑