C++实现简单双骰游戏

C++实现简单双骰游戏

随机数的生成:双骰游戏。投掷两个骰子,规则:
(1)第一次如果投出 7 或 11 点,玩家胜
(2)第一次如果投出 2,3 或 12 点,玩家输
(3)第一次如果投出 4, 5, 6, 8, 9, 10 点:
① 该点成为玩家的点数
② 玩家必须在投出 7 点之前投出玩家的点数,才能赢

#include<iostream>
#include<cstdlib>
using namespace std;

int dice(){
	srand(int(time(0)));
	return rand()%12+1;
}

void diceGame(){
	cout<<"请按任意键开始游戏"<<endl;
	cin.get();
	int Dnum = dice(); //the number of dice
	cout<<"您投掷的点数为:"<<Dnum<<endl;
	int Pnum1 = 0; //the first number of player
	int Pnum2 = 0; //the second number of player
	cout<<"按任意键继续"<<endl;
	cin.get();
	if(Dnum == 7||Dnum == 11){
		cout<<"恭喜您获得胜利!"<<endl;
	}else if(Dnum == 2||Dnum == 3||Dnum == 12){
		cout<<"很遗憾,您输了。"<<endl;
	}else{ //Dnum is 4,5,6,8,9,10
		Pnum1 = Dnum;
		while(1){
			cout<<"投掷结果为4到10,将重新投掷骰子"<<endl;
			cout<<"按任意键继续"<<endl;
			cin.get();
			Pnum2 = dice();
			cout<<"重新投掷骰子的结果为:"<<Pnum2<<endl;
			cout<<"按任意键继续"<<endl;
			cin.get();
			if(Pnum2 == 7){
				cout<<"很遗憾,您输了。"<<endl;
			}else{
				if(Pnum2 == Pnum1){
					cout<<"恭喜您获得胜利!"<<endl;
					break;
				}
			}
		}
		
	}
}

int main(){
	int i;
	for(i=0;i<5;i++){
		diceGame();
	}
	return 0;
}
posted @ 2022-01-30 15:32  草系编程苦手  阅读(574)  评论(0编辑  收藏  举报