PRML 6: SVD and PCA

 

 1. Eigendecomposition of Symmetric Matrix:

  (1) Solve the equation $det[\lambda I-A]=0$ to get eigenvalues $\lambda_1,\lambda_2,...,\lambda_n$;

  (2) Solve each $(\lambda_k I-A)\vec{x}=\vec{0}$ to get eigenvectors $\vec{v}_1,\vec{v}_2,...,\vec{v}_n$;

  (3) Orthogonalize and normalize the eigenvectors via Gram-Schimdt Process:

    for $k=1,2,...,n$: $\vec{v}_k=\vec{v}_k-\sum_{i=1}^{k-1}\frac{\vec{v}_k^T\vec{v}_i}{\vec{v}_i^T\vec{v}_i}\vec{v}_i$;

  (4) $A=V\Lambda V^T$, where $\Lambda=diag(\lambda_1,\lambda_2,...,\lambda_n)$ and $\vec{v}_k$ is the $k$th column of $V$.

  Please see my demo program of Orthogonal Diagonalization.

 

 2. Singular Value Decomposition (SVD):

  (1) Eigendecomposition of $A^T A$ ($A\in\mathbb{R}^{m\times n}$):

    eigenvalues $\lambda_1,\lambda_2,...,\lambda_n$ in decreasing order,

    and corresponding eigenvectors $\vec{v}_1,\vec{v}_2,...,\vec{v}_n$;

  (2) Singular Values: $\sqrt{\lambda_1},\sqrt{\lambda_2},...,\sqrt{\lambda_n}$;

    Left singular vectors: $\vec{u}_1,\vec{u}_2,...,\vec{u}_n$, where $\vec{u}_k=\frac{1}{\sqrt{\lambda_k}}A\vec{v}_k$;

    Right singular vectors: $\vec{v}_1,\vec{v}_2,...,\vec{v}_n$;

  (3) $A=U\Lambda V^T$, where $U\in\mathbb{R}^{m\times m}$, $\Lambda\in\mathbb{R}^{m\times n}$, $V\in\mathbb{R}^{n\times n}$.

 

 3. Principal Component Analysis (PCA):

  (1) Preprocessing of Dataset: 

    $\vec{\mu}_j = \frac{1}{N}\sum_{n=1}^N X_{nj}$, $\sigma_j=\sqrt{\frac{1}{N-1}\sum_{n=1}^N(X_{nj}-\vec{\mu}_j)}$, $X_{nj}=(X_{nj}-\vec{\mu}_j)/\sigma_j$;

  (2) Singular Value Decomposition:

    $X_{N\times D}\approx U_{N\times K}\Lambda_{K\times K}V_{K\times D}^T$;

  (3) $X_{N\times D}V_{D\times K}\approx U_{N\times K}\Lambda_{K\times K}=\widetilde{X}_{N\times K}$.

 

 

References:

  1. LeftNotEasy's blog: http://www.cnblogs.com/LeftNotEasy/archive/2011/01/19/svd-and-applications.html

  2. Bishop, Christopher M. Pattern Recognition and Machine Learning [M]. Singapore: Springer, 2006

 

posted on 2015-06-17 11:00  DevinZ  阅读(447)  评论(0编辑  收藏  举报

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