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摘要: 1033. To Fill or Not to Fill (25)时间限制10 ms内存限制65536 kB代码长度限制16000 B判题程序Standard作者ZHANG, GuochuanWith highways available, driving a car from Hangzhou t... 阅读全文
posted @ 2015-09-07 09:48 Deribs4 阅读(260) 评论(0) 推荐(0) 编辑
摘要: 1008. Elevator (20)时间限制400 ms内存限制65536 kB代码长度限制16000 B判题程序Standard作者CHEN, YueThe highest building in our city has only one elevator. A request list is... 阅读全文
posted @ 2015-09-06 21:45 Deribs4 阅读(163) 评论(0) 推荐(0) 编辑
摘要: 1089. Insert or Merge (25)时间限制200 ms内存限制65536 kB代码长度限制16000 B判题程序Standard作者CHEN, YueAccording to Wikipedia:Insertion sortiterates, consuming one input... 阅读全文
posted @ 2015-09-06 21:39 Deribs4 阅读(237) 评论(0) 推荐(0) 编辑
摘要: 1091. Acute Stroke (30)时间限制400 ms内存限制65536 kB代码长度限制16000 B判题程序Standard作者CHEN, YueOne important factor to identify acute stroke (急性脑卒中) is the volume o... 阅读全文
posted @ 2015-09-06 20:51 Deribs4 阅读(307) 评论(0) 推荐(0) 编辑
摘要: 1002. A+B for Polynomials (25)时间限制400 ms内存限制65536 kB代码长度限制16000 B判题程序Standard作者CHEN, YueThis time, you are supposed to find A+B where A and B are two ... 阅读全文
posted @ 2015-09-06 17:20 Deribs4 阅读(169) 评论(0) 推荐(0) 编辑
摘要: 1090. Highest Price in Supply Chain (25)时间限制200 ms内存限制65536 kB代码长度限制16000 B判题程序Standard作者CHEN, YueA supply chain is a network of retailers(零售商), distr... 阅读全文
posted @ 2015-09-06 16:19 Deribs4 阅读(251) 评论(0) 推荐(0) 编辑
摘要: 1088. Rational Arithmetic (20)时间限制200 ms内存限制65536 kB代码长度限制16000 B判题程序Standard作者CHEN, YueFor two rational numbers, your task is to implement the basic ... 阅读全文
posted @ 2015-09-06 15:24 Deribs4 阅读(243) 评论(0) 推荐(0) 编辑
摘要: 1087. All Roads Lead to Rome (30)时间限制200 ms内存限制65536 kB代码长度限制16000 B判题程序Standard作者CHEN, YueIndeed there are many different tourist routes from our cit... 阅读全文
posted @ 2015-09-06 11:49 Deribs4 阅读(1559) 评论(0) 推荐(0) 编辑
摘要: 1086. Tree Traversals Again (25)时间限制200 ms内存限制65536 kB代码长度限制16000 B判题程序Standard作者CHEN, YueAn inorder binary tree traversal can be implemented in a non... 阅读全文
posted @ 2015-09-06 09:18 Deribs4 阅读(180) 评论(0) 推荐(0) 编辑
摘要: 1 基本操作(1)头文件#include(2)创建vector对象,vector vec;(3)尾部插入数字:vec.push_back(a);(4)使用下标访问元素,cout::iterator it; 2 for(it=vec.begin();it!=vec.end();it++) 3 cout... 阅读全文
posted @ 2015-09-06 00:20 Deribs4 阅读(368) 评论(0) 推荐(0) 编辑
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