pat1083. List Grades (25)

1083. List Grades (25)

时间限制

400 ms

内存限制

65536 kB

代码长度限制

16000 B

判题程序

Standard

作者

CHEN, Yue

Given a list of N student records with name, ID and grade. You are supposed to sort the records with respect to the grade in non-increasing order, and output those student records of which the grades are in a given interval.

Input Specification:

Each input file contains one test case. Each case is given in the following format:

N
name[1] ID[1] grade[1]
name[2] ID[2] grade[2]
... ...
name[N] ID[N] grade[N]
grade1 grade2

where name[i] and ID[i] are strings of no more than 10 characters with no space, grade[i] is an integer in [0, 100], grade1 and grade2 are the boundaries of the grade's interval. It is guaranteed that all the grades are distinct.

Output Specification:

For each test case you should output the student records of which the grades are in the given interval [grade1, grade2] and are in non-increasing order. Each student record occupies a line with the student's name and ID, separated by one space. If there is no student's grade in that interval, output "NONE" instead.

Sample Input 1:

4
Tom CS000001 59
Joe Math990112 89
Mike CS991301 100
Mary EE990830 95
60 100

Sample Output 1:

Mike CS991301
Mary EE990830
Joe Math990112

Sample Input 2:

2
Jean AA980920 60
Ann CS01 80
90 95

Sample Output 2:

NONE

---

提交代码

 

#include<cstdio>
#include<stack>
#include<algorithm>
#include<iostream>
#include<stack>
#include<set>
#include<map>
using namespace std;
map<int,pair<string,string> > ha;//成绩-姓名-id
int main(){
    //freopen("D:\\INPUT.txt","r",stdin);
    int n;
    scanf("%d",&n);
    int i,g1,g2;
    string name,id;
    int grade;
    for(i=0;i<n;i++){
        cin>>name>>id;
        scanf("%d",&grade);
        ha[grade]=make_pair(name,id);
    }
    int temp;
    scanf("%d %d",&g1,&g2);
    if(g1>g2){
        temp=g1;
        g1=g2;
        g2=temp;
    }
    temp=0;
    map<int,pair<string,string> >::reverse_iterator it;
    for(it=ha.rbegin();it!=ha.rend();it++){
        if(it->first>=g1&&it->first<=g2){
            cout<<(it->second).first<<" "<<(it->second).second<<endl;
            temp++;
        }
    }
    if(!temp){
        printf("NONE\n");
    }
    return 0;
}