pat1050. String Subtraction (20)

1050. String Subtraction (20)

时间限制

10 ms

内存限制

65536 kB

代码长度限制

16000 B

判题程序

Standard

作者

CHEN, Yue

Given two strings S₁ and S₂, S = S₁ - S₂ is defined to be the remaining string after taking all the characters in S₂ from S₁. Your task is simply to calculate S₁ - S₂ for any given strings. However, it might not be that simple to do it fast.

Input Specification:

Each input file contains one test case. Each case consists of two lines which gives S₁ and S₂, respectively. The string lengths of both strings are no more than 10⁴. It is guaranteed that all the characters are visible ASCII codes and white space, and a new line character signals the end of a string.

Output Specification:

For each test case, print S₁ - S₂ in one line.

Sample Input:

They are students.
aeiou

Sample Output:

Thy r stdnts.

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提交代码

 

#include<cstdio>
#include<algorithm>
#include<iostream>
#include<cstring>
#include<queue>
#include<vector>
#include<cmath>
#include<string>
#include<map>
#include<set>
using namespace std;
bool ha[128];//ACSII码范围  0-127
int main(){
    //freopen("D:\\INPUT.txt","r",stdin);
    string s1,s2,s3;
    getline(cin,s1);
    getline(cin,s2);
    int i;
    for(i=0;i<s2.length();i++){
        ha[s2[i]]=true;
    }
    s3="";
    for(i=0;i<s1.length();i++){
        if(!ha[s1[i]]){
            s3=s3+s1[i];
        }
    }
    cout<<s3<<endl;
    return 0;
}