oracle 关联更新

不多说了,我们来做实验吧。

创建如下表数据

select * from t1 ;

select * from t2;

现需求:参照T2表,修改T1表,修改条件为两表的fname列内容一致。

方式1,update

常见陷阱:

UPDATE T1 
SET T1.FMONEY = (select T2.FMONEY from t2 where T2.FNAME = T1.FNAME)

执行后T1结果如下:

有一行原有值,被更新成空值了。

正确写法:

UPDATE T1 
SET T1.FMONEY = (select T2.FMONEY from t2 where T2.FNAME = T1.FNAME)
WHERE EXISTS(SELECT 1 FROM T2 WHERE T2.FNAME = T1.FNAME);

方式2:内联视图更新

UPDATE (
select t1.fmoney  fmoney1,t2.fmoney  fmoney2 from t1,t2 where t1.fname = t2.fname
)t
set fmoney1 =fmoney2;

方式3:merge更新

merge into t1
using (select t2.fname,t2.fmoney from t2) t
on (t.fname = t1.fname)
when matched then 
  update  set t1.fmoney = t.fmoney;
posted @ 2019-08-13 16:47  流失的痕迹  阅读(281)  评论(0编辑  收藏  举报