HDU1019

Least Common Multiple

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 20759    Accepted Submission(s): 7738

Problem Description
The least common multiple (LCM) of a set of positive integers is the smallest positive integer which is divisible by all the numbers in the set. For example, the LCM of 5, 7 and 15 is 105.
 
Input
Input will consist of multiple problem instances. The first line of the input will contain a single integer indicating the number of problem instances. Each instance will consist of a single line of the form m n1 n2 n3 ... nm where m is the number of integers in the set and n1 ... nm are the integers. All integers will be positive and lie within the range of a 32-bit integer.
 
Output
For each problem instance, output a single line containing the corresponding LCM. All results will lie in the range of a 32-bit integer.
 
Sample Input
2 3 5 7 15 6 4 10296 936 1287 792 1
 
Sample Output
105 10296
 
 
 
  1. #include<iostream>
  2. #include<cstdio>
  3. using namespace std;
  4. int a[10000];
  5. int gcd(int a,int b)
  6. {  
  7. if(b==0)   
  8. return a;
  9.  return gcd(b,a%b);
  10. }
  11. int lcm(int a,int b)
  12. {
  13.  return a/gcd(a,b)*b; }
  14. int main()
  15. {
  16.  int i,j,t;  
  17. scanf("%d",&t);
  18.  while(t--)
  19.  {  
  20.  int temp,n;
  21.   scanf("%d",&n);
  22.   for(i=0;i<n;i++)  
  23.  {    
  24. scanf("%d",&a[i]);
  25.   }
  26.   temp=a[0];  
  27.  for(i=1;i<n;i++)
  28.   {
  29.   temp=lcm(temp,a[i]);
  30.   }   
  31. printf("%d\n",temp);
  32.     }   
  33. return 0;
  34. }
 
posted @ 2013-03-04 19:46  哥的笑百度不到  阅读(358)  评论(0编辑  收藏  举报