python 身份证校验位计算

以后可能用得到

# -*- coding:gbk -*- 
#S+=Sum(Ai*Wi);
#Ti[S%11]
import sys

class IdentityCard:
    def __init__( self ):
        self.__Wi = [7, 9, 10, 5, 8, 4, 2, 1, 6, 3, 7, 9, 10, 5, 8, 4, 2]
        self.__Ti = ['1', '0', 'x', '9', '8', '7', '6', '5', '4', '3', '2']

    def check( self, code ):
        if (len(code) != 17):
            print "必须为17位的字符"
            return False
        return True
        
    def calculate( self, code ):
        sum = 0
        for i in range(17):
            sum += int(code[i])*self.__Wi[i]
        return self.__Ti[sum%11]
        
def test():
    ic = IdentityCard()
    code = "33000000000000000" #17位身份证
    if ic.check(code):
        print "你的校验位为:%s"%ic.calculate(code)
        
if __name__ == '__main__':
    test()