WPF 之 UI 异步交互 

1 System.Windows.Application.Current.Dispatcher.BeginInvoke(new Action(()=> {
2 
3 　　//···················
4 
5 }))
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posted @ 2017-04-11 10:18  Hao0  阅读(160)  评论(0)  编辑  收藏  举报