JS 修改集合中某一个字段的名称

假设你有一个包含以下数据的集合：

const books = [
  { title: 'The Alchemist', author: 'Paulo Coelho', year: 1988, genre: 'Fiction', pages: 163 },
  { title: 'To Kill a Mockingbird', author: 'Harper Lee', year: 1960, genre: 'Fiction', pages: 281 },
  { title: '1984', author: 'George Orwell', year: 1949, genre: 'Science Fiction', pages: 328 },
  { title: 'Pride and Prejudice', author: 'Jane Austen', year: 1813, genre: 'Romance', pages: 435 },
  { title: 'The Great Gatsby', author: 'F. Scott Fitzgerald', year: 1925, genre: 'Fiction', pages: 180 }
];

现在，我们想要将 year 字段改为 publicationYear。你可以使用 map 方法和对象解构来实现这个目标：

const booksWithPublicationYear = books.map(({ year, ...rest }) => {
  return { publicationYear: year, ...rest };
});

console.log(booksWithPublicationYear);

这将返回以下结果：

[
  { publicationYear: 1988, title: 'The Alchemist', author: 'Paulo Coelho', genre: 'Fiction', pages: 163 },
  { publicationYear: 1960, title: 'To Kill a Mockingbird', author: 'Harper Lee', genre: 'Fiction', pages: 281 },
  { publicationYear: 1949, title: '1984', author: 'George Orwell', genre: 'Science Fiction', pages: 328 },
  { publicationYear: 1813, title: 'Pride and Prejudice', author: 'Jane Austen', genre: 'Romance', pages: 435 },
  { publicationYear: 1925, title: 'The Great Gatsby', author: 'F. Scott Fitzgerald', genre: 'Fiction', pages: 180 }
]

在这个例子中，我们使用对象解构来将 year 字段赋值给变量 year，并使用剩余参数将其余的字段存储在 rest 中。然后，我们返回一个新的对象，该对象包含了重新命名的 publicationYear 字段和剩余的字段。最后，booksWithPublicationYear 数组包含了更新的信息，以满足我们的需求。