[ 9.29 ]CF每日一题系列—— 765B字符串规律

Description:
  遇到了ogo可以变成***如果ogo后面有go统统忽略,输出结果

Solution:
  哎如果我一开始对题意的解读如上的话,就不会被整的那么麻烦了

Code:
  

#include <iostream>
#include <cstdio>
#include <cstring>
using namespace std;
const int maxn = 150;
/***找到一个题目的规律,做题的方法是多么的重要!!***/
/***以后没有好的方法,不打代码***/
char s[maxn];
int main()
{
    int len;
    while(~scanf("%d%s",&len,s))
    {
        for(int i = 0;i < len;)
        {
            if(s[i] == 'o' && s[i + 1] == 'g' && s[i + 2] == 'o')
            {
                printf("***");
                i += 3;
                while(s[i] == 'g' && s[i+1] == 'o')
                {
                    i += 2;
                }
            }
            else
            {
                printf("%c",s[i]);
                i++;
            }
        }
        printf("\n");
    }
    return 0;
}

 看看我的超级麻烦bug多多的模拟!!!

一开始真的读错题了!

#include <iostream>
#include <cstring>
#include <cstdio>
#include <algorithm>

using namespace std;
const int maxn = 1e3;
char s[maxn];
char out[maxn];
char cmp[200] = "ogogogogogogogogogogogogogogogogogogogogogogogogogogogogogogogogogogogogogogogogogogogogogogogogogogogogogogo";
int main()
{
    int len;
    while(~scanf("%d",&len))
    {
        scanf("%s",s);
        int mpid = 0;
        int outsid = 0;
        for(int i = 0;i < len;++i)
        {
            out[outsid++] = s[i];
            if(s[i] == cmp[mpid])
            {
                //printf(" %d\n",mpid);
                mpid++;
            }
            else
            {
                //cout<<mpid<<endl;
                if(mpid == 1)
                {
                    outsid -= 1;
                    i -= 1;
                }
                else if(mpid == 2)
                {
                    mpid = 0;
                }
                else if(mpid % 2 == 1)
                {
                    outsid -= mpid + 1;
                    out[outsid++] = '*';
                    out[outsid++] = '*';
                    out[outsid++] = '*';
                    i--;
                }
                else if(mpid % 2 == 0 && mpid != 0)
                {
                    outsid -= mpid + 1;
                    out[outsid++] = '*';
                    out[outsid++] = '*';
                    out[outsid++] = '*';
                    out[outsid++] = 'g';
                    out[outsid++] = s[i];
                }
                mpid = 0;
            }
        }
        if(mpid > 2)
        {
            if(mpid % 2 == 1)
            {
                outsid -= mpid;
                out[outsid++] = '*';
                out[outsid++] = '*';
                out[outsid++] = '*';
            }
            else if(mpid % 2 == 0)
            {
                outsid -= mpid;
                out[outsid++] = '*';
                out[outsid++] = '*';
                out[outsid++] = '*';
                out[outsid++] = 'g';
            }
        }
        out[outsid] = '\0';
        printf("%s\n",out);
    }
    return 0;
}

 

posted @ 2018-09-29 20:20  Butterflier  阅读(154)  评论(0编辑  收藏  举报