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sql报错: Every derived table must have its own alias

用的是mysql数据库

 1 UPDATE tb_cr_circulate_gtsc 
 2 set path_status='A06'
 3 where
 4 order_id='Ph800601211123155507'
 5 and
 6 receive_role='21075116-001'
 7 and
 8 receive_role_name='024722cd-b197-462f-bdc2-f0423d88e580&Z&11caea25-4996-4682-aa3c-ea698e5140cc&21075116-001&四川省川东农药化工有限公司'
 9 and 
10 ( 
11 (SELECT statusSum from   (select COUNT(path_status)  as statusSum FROM tb_cr_circulate_gtsc  where order_id='Ph800601211123155507' and path_status='A04' and is_current_point='1' ) )
12 <  
13 (SELECT statusSum from  (select COUNT(path_status)  as statusSum  FROM tb_cr_circulate_gtsc where order_id='Ph800601211123155507' and is_current_point='1') )
14 )

报错提示:每一个派生出来的表都必须有一个自己的别名

解决方式:在新产生表的地方加上别名

1 ( 
2 (SELECT statusSum from   (select COUNT(path_status)  as statusSum FROM tb_cr_circulate_gtsc  where order_id='Ph800601211123155507' and path_status='A04' and is_current_point='1' ) as a)
3 <  
4 (SELECT statusSum from  (select COUNT(path_status)  as statusSum  FROM tb_cr_circulate_gtsc where order_id='Ph800601211123155507' and is_current_point='1') as a )
5 )

 

posted @ 2021-12-01 09:34  DDD-SagerKing  阅读(172)  评论(0编辑  收藏  举报