Find The Multiple POJ - 1426
Given a positive integer n, write a program to find out a nonzero multiple m of n whose decimal representation contains only the digits 0 and 1. You may assume that n is not greater than 200 and there is a corresponding m containing no more than 100 decimal digits.
Input
The input file may contain multiple test cases. Each line contains a value of n (1 <= n <= 200). A line containing a zero terminates the input.
Output
For each value of n in the input print a line containing the corresponding value of m. The decimal representation of m must not contain more than 100 digits. If there are multiple solutions for a given value of n, any one of them is acceptable.
Sample Input
2 6 19 0
Sample Output
10 100100100100100100 111111111111111111
#include<iostream> #include<vector> #include<string> #include<queue> #include<memory.h> #include<algorithm> typedef unsigned long long ull; using namespace std; ull n; ull ans; bool vis[1005]; void dfs(ull num,int depth) { if (ans)return; if (num%n == 0) { ans = num; return; } else { if (depth == 19)return; dfs(num * 10, depth + 1); dfs(num * 10 + 1, depth + 1); } } int main() { while (cin >> n) { if (n == 0)break; ans = 0; dfs(1, 0); printf("%I64u\n", ans); } return 0; }
posted on 2018-08-17 10:55 Cute_Abacus 阅读(88) 评论(0) 编辑 收藏 举报