C语言实现井子格游戏

C语言简单实现一个9宫格的井子格游戏，任意一方完成三连即获胜！

    int winner = 0;
    int player = 0;
    int col = 0;
    int row = 0;
    int choice = 0;
    char board[3][3] = {
        {'1','2','3'},
        {'4','5','6'},
        {'7','8','9'}
    };
    for (int i = 0; i < 9 && winner == 0; i++) {
        printf("\n\n");
        printf(" %c | %c | %c \n",board[0][0],board[0][1],board[0][2]);
        printf("---+---+---\n");
        printf(" %c | %c | %c \n",board[1][0],board[1][1],board[1][2]);
        printf("---+---+---\n");
        printf(" %c | %c | %c \n",board[2][0],board[2][1],board[2][2]);

        player = i % 2 + 1;
        do {
            printf("玩家%d请输入你要选择的位置来放置%c：",player,(player == 1)?'X':'Z');
            scanf("%d",&choice);
            col = --choice % 3;
            row = choice / 3;
        } while (choice < 0 || choice > 8 || board[row][col] > 57);
        board[row][col] = player == 1 ? 'X' : 'Z';
        /****判断是否有人胜出*****/
        if ((board[0][0]==board[1][1]&&board[0][0]==board[2][2])  
             ||(board[0][2]==board[1][1]&&board[0][2]==board[2][0])) {
            winner = player;
        }else{
            for (int i = 0; i < 3; i++) {
                if ((board[i][0]==board[i][1]&&board[i][0]==board[i][2])
                     ||(board[0][i]==board[1][i]&&board[0][i]==board[2][i])) {
                    winner = player;
                }
            }
        }
    }
    printf("\n\n");
    printf(" %c | %c | %c \n",board[0][0],board[0][1],board[0][2]);
    printf("---+---+---\n");
    printf(" %c | %c | %c \n",board[1][0],board[1][1],board[1][2]);
    printf("---+---+---\n");
    printf(" %c | %c | %c \n",board[2][0],board[2][1],board[2][2]);
    printf("**********玩家%d赢了！！！**********\n\n",winner);