C++随笔
- 虚析构函数是可以声明的,这意味着需要由于子类来实现接口的析构函数。
reference: https://blog.csdn.net/wufeifan_learner/article/details/88804072
class A{
public:
A(){
cout<<"构造函数A"<<endl;
}
virtual ~A() = 0;
};
class B: public A{
public:
B(){
cout<<"构造函数B"<<endl;
}
~B(){
//TODO
}
- 待续