Django之上传文件

使用Form表单上传文件

  • upload.html
<!DOCTYPE html>
<html lang="en">
<head>
    <meta charset="UTF-8">
    <title>Title</title>
</head>
<body>

    {#  上传文件的时候必须要在form标签中添加属性 enctype="multipart/form-data"  #}
    <form method="POST" action="/upload/" enctype="multipart/form-data">

        <input type="text" name="user" />
        <input type="file" name="img" />
        <input type="submit" />

    </form>

</body>
</html>

  • views.py
from django.shortcuts import render

import os
# Create your views here.


def upload(request):

    if request.method == "POST":
        user = request.POST.get("user")
        # img = request.POST.get("img")     # 所有提交的文件名

        img = request.FILES.get('img')      # 所有提交的文件

        img_name = img.name    # 获取文件名
        img_abs_name = os.path.join("static", img_name)
        with open(img_abs_name, "wb") as f:
            for chunk in img.chunks():
                f.write(chunk)

    return render(request, 'upload.html')

上传完之后可以通过链接 “http://127.0.0.1:8000/static/文件名” 打开图片

使用js原生XMLHttpRequest对象进行ajax上传文件

  • upload.html
<!DOCTYPE html>
<html lang="en">
<head>
    <meta charset="UTF-8">
    <title>Title</title>
</head>
<body>

    <input type="text" id="user" name="user" />
    <input type="file" id="img" name="img" />
    <input type="button" value="上传图片" onclick="uploadFile1();"/>

    <script>

         // 使用原生的 XMLHttpRequest 上传图片
        function uploadFile1() {
            var form = new FormData();
            form.append("user", document.getElementById("user").value);

            // 获取文件对象
            var fileObj = document.getElementById("img").files[0];
            form.append("img", fileObj);

            var xhr = new XMLHttpRequest();
            xhr.onreadystatechange = function () {
                if (xhr.readyState == 4){
                    // 已经接受到全部响应数据,执行以下操作
                    var data = xhr.responseText;
                    console.log(data);
                }
            };

            xhr.open("POST", "/upload/", true);
            xhr.send(form);
        }
    </script>

</body>
</html>

  • views.py
from django.shortcuts import render
from django.shortcuts import HttpResponse

import os
# Create your views here.


def upload(request):

    if request.method == "POST":
        user = request.POST.get("user")
        # img = request.POST.get("img")     # 所有提交的文件名

        img = request.FILES.get('img')      # 所有提交的文件

        img_name = img.name
        img_abs_name = os.path.join("static", img_name)
        with open(img_abs_name, "wb") as f:
            for chunk in img.chunks():
                f.write(chunk)

        return HttpResponse("ok")

    return render(request, 'upload.html')

使用jQuery 的ajax上传文件

该方法需要借助js原生的FormData()将数据封装到该对象中,并且不支持低版本的浏览器,例如ie5、ie6

  • upload.html
<!DOCTYPE html>
<html lang="en">
<head>
    <meta charset="UTF-8">
    <title>Title</title>
</head>
<body>

    <input type="text" id="user" name="user" />
    <input type="file" id="img" name="img"  />
    <input type="button" value="上传图片" onclick="jQueryAjax();"/>

    <script src="/static/jquery/jquery-1.12.4.js"></script>
    <script>

        function jQueryAjax() {

            // 获取文件对象
            var fileObj = $("#img")[0].files[0]; 

            // 创建FormData对象
            var form = new FormData();
            
            // 将数据封装到对象中
            form.append("img", fileObj);
            form.append("user", "aa");

            $.ajax({
                type: "POST",
                url: "/upload/",
                data: form,
                processData: false,    
                contentType: false,    # 不设置请求头
                sucess: function (arg) {
                    console.log(arg);
                }
            })
        }
    </script>

</body>
</html>

  • views.py
from django.shortcuts import render
from django.shortcuts import HttpResponse

import os
import json
# Create your views here.


def upload(request):

    if request.method == "POST":
        user = request.POST.get("user")
        # img = request.POST.get("img")     # 所有提交的文件名

        img = request.FILES.get('img')      # 所有提交的文件

        img_name = img.name
        img_abs_name = os.path.join("static", img_name)
        print(img_abs_name)
        with open(img_abs_name, "wb") as f:
            for chunk in img.chunks():
                f.write(chunk)

        return HttpResponse("ok")

    return render(request, 'upload.html')

使用jQuery 的ajax + iframe 解决浏览器兼容性的问题

  • upload1.html
<!DOCTYPE html>
<html lang="en">
<head>
    <meta charset="UTF-8">
    <title>Title</title>
    <style>

        #container img{
            width: 100px;
            height: 100px;

        }
    </style>
</head>
<body>

    <iframe id="my_iframe" name="my_iframe" style="display:none" src="" ></iframe>

    <form id="fo" method="POST" action="/upload1/" enctype="multipart/form-data">
        <input type="text" id="user" name="user" />
        <input type="file" id="img" name="img" onchange="uploadFile();" />
        <input type="submit">

    </form>

    <div id="container">

    </div>

    <script src="/static/jquery/jquery-1.12.4.js"></script>
    <script>

        function uploadFile() {
            $("#container").find("img").remove();
            document.getElementById("my_iframe").onload = callback;
            document.getElementById("fo").target = "my_iframe";
            document.getElementById("fo").submit();
        }

        function callback() {
            
            // 想获取iframe中的标签必须使用.contents来获取
            var text = $("#my_iframe").contents().find('body').text();
            var json_data = JSON.parse(text);

            if (json_data.status){
                // 上传成功
                // 生成img标签,预览刚才上传成功的图片

                var tag = document.createElement("img");
                tag.src = "/" + json_data.data;
                tag.className = "img";
                $("#container").append(tag);
            }else{
                alert(json_data.error);
            }
        }

    </script>
</body>
</html>

  • views.py
from django.shortcuts import render
from django.shortcuts import HttpResponse

import os
import json
# Create your views here.

def upload1(request):
    if request.method == "POST":
        ret = {
            "status": False,
            "data": None,
            "error": None,
        }

        try:
            img = request.FILES.get("img")
            img_name = img.name
            img_abs_name = os.path.join("static", img_name)
            print(img_abs_name)
            with open(img_abs_name, "wb") as f:
                for chunk in img.chunks():
                    f.write(chunk)
            ret["status"] = True
            ret["data"] = img_abs_name

        except Exception as e:
            ret["error"] = str(e)

        return HttpResponse(json.dumps(ret))

    return render(request, "upload1.html")

posted on 2016-09-25 10:09  奋斗中的码农  阅读(306)  评论(0编辑  收藏  举报

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