多线程编程(9)Barrier

2010-11-19 10:58 Clingingboy 阅读(956) 评论(2) 编辑收藏举报

魔兽世界组队下副本

下副本一般都要找5个人,一般玩家都在副本门口等,然后等待其他玩家跑过来

即玩家在做两个动作

1.跑到副本门口

2.等5个人到齐了，然后进副本.

如果玩家先到就得等其他玩家到了才可以下副本，即大家跑到副本门口的时间是不同的，但进副本的时间是相同的(保持线程同步).

示例代码如下

public class Demo6
{
    Barrier barrier=new Barrier(5);
    public Demo6()
    {
        ThreadPool.QueueUserWorkItem(new WaitCallback(Task1));
        ThreadPool.QueueUserWorkItem(new WaitCallback(Task2));
        ThreadPool.QueueUserWorkItem(new WaitCallback(Task3));
        ThreadPool.QueueUserWorkItem(new WaitCallback(Task4));
        ThreadPool.QueueUserWorkItem(new WaitCallback(Task5));
    }

    public void Task1(object obj)
    {
        Thread.Sleep(1000);
        Console.WriteLine(DateTime.Now);
        Console.WriteLine("Task1");
        barrier.SignalAndWait();
        Console.WriteLine("Task1 DoConcurrent");
    }

    public void Task2(object obj)
    {
        Thread.Sleep(2000);
        Console.WriteLine(DateTime.Now);
        Console.WriteLine("Task2");
        barrier.SignalAndWait();
        Console.WriteLine("Task2 DoConcurrent");
    }

    public void Task3(object obj)
    {
        Thread.Sleep(3000);
        Console.WriteLine(DateTime.Now);
        Console.WriteLine("Task3");
        barrier.SignalAndWait();
        Console.WriteLine("Task3 DoConcurrent");
    }

    public void Task4(object obj)
    {
        Thread.Sleep(4000);
        Console.WriteLine(DateTime.Now);
        Console.WriteLine("Task4");
        barrier.SignalAndWait();
        Console.WriteLine("Task4 DoConcurrent");
    }

    public void Task5(object obj)
    {
        Thread.Sleep(5000);
        Console.WriteLine(DateTime.Now);
        Console.WriteLine("Task5");
        barrier.SignalAndWait();
        Console.WriteLine("Task5 DoConcurrent");
    }
}