bzoj3064 CPU监控

今天终于写了一道正常的题

思路是这样的:

1.普通线段树add,set不变,并改为下放标记版本

2.past_addv 记录一个区间内可能的addv值的最大值

3.past_setv 记录一个区间被set的最大值

4.maxv与past_maxv为值

 

代码风格导致比较长

  1 #include<cstdio>
  2 #include<climits>
  3 #include<cctype>
  4 #include<algorithm>
  5 
  6 using std :: max ;
  7 
  8 const int MAXN = 1024 * 128 + 20 ;
  9 const int NONE = INT_MIN ;
 10 int N ;
 11 
 12 void max_equal ( int & a , const int b ) {
 13     if ( b > a ) a = b ;
 14 }
 15 
 16 int get_int () {
 17     int v ;
 18     scanf ( "%d" , & v ) ;
 19     return v ;
 20 }
 21 
 22 int addv [ MAXN * 2 ] ;
 23 int setv [ MAXN * 2 ] ;
 24 int maxv [ MAXN * 2 ] ;
 25 
 26 int past_addv [ MAXN * 2 ] ;
 27 int past_setv [ MAXN * 2 ] ;
 28 int past_maxv [ MAXN * 2 ] ; 
 29 
 30 void M_add ( const int o , const int v ) {
 31     if ( setv [ o ] != NONE ) {
 32         setv [ o ] += v ; max_equal ( past_setv [ o ] , setv [ o ] ) ;
 33     } else {
 34         addv [ o ] += v ; max_equal ( past_addv [ o ] , addv [ o ] ) ;
 35     }
 36 }
 37 
 38 void M_set ( const int o , const int v ) {
 39     setv [ o ] = v ; max_equal ( past_setv [ o ] , setv [ o ] ) ;
 40 }
 41 
 42 void P_add ( const int o , const int v ) {
 43     if ( setv [ o ] != NONE ) {
 44         max_equal ( past_setv [ o ] , setv [ o ] + v ) ;
 45     } else {
 46         max_equal ( past_addv [ o ] , addv [ o ] + v ) ;
 47     }
 48 }
 49 
 50 void P_set ( const int o , const int v ) {
 51     max_equal ( past_setv [ o ] , v ) ;
 52 }
 53 
 54 void push_down ( const int o ) {
 55     const int o1 = o << 1 ;
 56     const int o2 = o << 1 | 1 ; 
 57     if ( past_addv [ o ] ) {
 58         P_add ( o1 , past_addv [ o ] ) ;
 59         P_add ( o2 , past_addv [ o ] ) ;
 60         past_addv [ o ] = 0 ;
 61     }
 62     if ( addv [ o ] ) {
 63         M_add ( o1 , addv [ o ] ) ;
 64         M_add ( o2 , addv [ o ] ) ;
 65         addv [ o ] = 0 ;
 66     }
 67     if ( past_setv [ o ] != NONE ) {
 68         P_set ( o1 , past_setv [ o ] ) ;
 69         P_set ( o2 , past_setv [ o ] ) ;
 70         past_setv [ o ] = NONE ;
 71     }
 72     if ( setv [ o ] != NONE ) {
 73         M_set ( o1 , setv [ o ] ) ;
 74         M_set ( o2 , setv [ o ] ) ;
 75         setv [ o ] = NONE ;
 76     }
 77 }
 78 
 79 void maintain ( const int o , const int L , const int R ) {
 80     const int o1 = o << 1 ;
 81     const int o2 = o << 1 | 1 ;
 82     if ( R - L == 1 ) {
 83         maxv [ o ] = setv [ o ] ;
 84         max_equal ( past_maxv [ o ] , past_setv [ o ] ) ; 
 85     } else {
 86         maxv [ o ] = 
 87             ( setv [ o ] == NONE ) ? max ( maxv [ o1 ] , maxv [ o2 ] ) + addv [ o ] : setv [ o ] ;
 88         max_equal ( past_maxv [ o ] , past_setv [ o ] ) ;
 89         max_equal ( past_maxv [ o ] , max ( maxv [ o1 ] , maxv [ o2 ] ) + past_addv [ o ] ) ;
 90         max_equal ( past_maxv [ o ] , max ( past_maxv [ o1 ] , past_maxv [ o2 ] ) ) ;
 91     }
 92 }
 93 
 94 static struct {
 95     void W ( const int o , const int L , const int R ) {
 96         setv [ o ] = past_setv [ o ] = maxv [ o ] = past_maxv [ o ] = NONE ;
 97         addv [ o ] = past_addv [ o ] = 0 ;
 98         if ( R - L == 1 ) {
 99             M_set ( o , get_int () ) ;
100         } else {
101             const int M = ( L + R ) >> 1 ;
102             W ( o << 1 , L , M ) ;
103             W ( o << 1 | 1 , M , R ) ;
104         }
105         maintain ( o , L , R ) ;
106     }
107     void operator ( ) ( ) {
108         scanf ( "%d" , & N ) ;
109         W ( 1 , 1 , N + 1 ) ;
110     }
111 } Build ;
112 
113 
114 static struct {
115     int l , r , v ;
116     void W ( const int o , const int L , const int R ) {
117         if ( l <= L && R <= r ) {
118             M_set ( o , v ) ;
119         } else {
120             const int M = ( L + R ) >> 1 ;
121             push_down ( o ) ;
122             if ( l < M ) W ( o << 1 , L , M ) ; else maintain ( o << 1 , L , M ) ;
123             if ( M < r ) W ( o << 1 | 1 , M , R ) ; else maintain ( o << 1 | 1 , M , R ) ;
124         }
125         maintain ( o , L , R ) ;
126     }
127     void operator () ( const int L , const int R , const int V ) {
128         l = L ; r = R + 1 ; v = V ;
129         W ( 1 , 1 , N + 1 ) ;
130     }
131 } Set ;
132 
133 static struct {
134     int l , r , v ;
135     void W ( const int o , const int L , const int R ) {
136         if ( l <= L && R <= r ) {
137             M_add ( o , v ) ;
138         } else {
139             const int M = ( L + R ) >> 1 ;
140             push_down ( o ) ;
141             if ( l < M ) W ( o << 1 , L , M ) ; else maintain ( o << 1 , L , M ) ;
142             if ( M < r ) W ( o << 1 | 1 , M , R ) ; else maintain ( o << 1 | 1 , M , R ) ;
143         }
144         maintain ( o , L , R ) ;
145     }
146     void operator () ( const int L , const int R , const int V ) {
147         l = L ; r = R + 1 ; v = V ;
148         W ( 1 , 1 , N + 1 ) ;
149     }
150 } Add ;
151 
152 static struct {
153     int l , r , ans ;
154     void W ( const int o , const int L , const int R ) {
155         if ( l <= L && R <= r ) {
156             max_equal ( ans , maxv [ o ] ) ;
157         } else {
158             const int M = ( L + R ) >> 1 ;
159             push_down ( o ) ; 
160             maintain ( o << 1 , L , M ) ;
161             maintain ( o << 1 | 1 , M  , R ) ;
162             if ( l < M ) W ( o << 1 , L , M ) ;
163             if ( M < r ) W ( o << 1 | 1 , M , R ) ;
164         }
165     }
166     int operator () ( const int L , const int R ) {
167         l = L ;  r = R + 1 ; ans = NONE ;
168         W ( 1 , 1 , N + 1 ) ;
169         return ans ;
170     }
171 } Qmax ;
172 
173 static struct {
174     int l , r , ans ;
175     void W ( const int o , const int L , const int R ) {
176         if ( l <= L && R <= r ) {
177             max_equal ( ans , past_maxv [ o ] ) ;
178         } else {
179             const int M = ( L + R ) >> 1 ;
180             push_down ( o ) ; 
181             maintain ( o << 1 , L , M ) ;
182             maintain ( o << 1 | 1 , M  , R ) ;
183             if ( l < M ) W ( o << 1 , L , M ) ;
184             if ( M < r ) W ( o << 1 | 1 , M , R ) ;
185         }
186     }
187     int operator () ( const int L , const int R ) {
188         l = L ;  r = R + 1 ; ans = NONE ;
189         W ( 1 , 1 , N + 1 ) ;
190         return ans ;
191     }
192 } Q_past_max ;
193 
194 int T , E , opt , X , Y , Z ;
195 int main () {
196     Build ( ) ;
197     scanf ( "%d" , & E ) ;
198     while ( E -- ) {
199         while ( isspace ( opt = getchar () ) ) ;
200         switch ( opt ) {
201             case 'Q' :
202                 scanf ( "%d%d" , & X , & Y ) ;
203                 printf ( "%d\n" , Qmax ( X , Y ) ) ;
204                 break ;
205             case 'A' :
206                 scanf ( "%d%d" , & X , & Y ) ;
207                 printf ( "%d\n" , Q_past_max ( X , Y ) ) ;
208                 break ;
209             case 'P' :
210                 scanf ( "%d%d%d" , & X , & Y , & Z ) ;
211                 Add ( X , Y , Z ) ;
212                 break ;
213             case 'C' :
214                 scanf ( "%d%d%d" , & X , & Y , & Z ) ;
215                 Set ( X , Y , Z ) ;
216                 break ;
217         }
218     }
219     return 0 ;
220 }

 

posted @ 2016-01-13 13:46  Chris_2  阅读(642)  评论(0编辑  收藏  举报