摘要:
有如下循环体:hits:=0;for I:=0 to NumberOfIterations-1 dobegin {perform some calculations dependent on random number generation to determine a value x} if x>0 then hits:=hits+1;end;{For Loop}FailureProbability:=hits/NumberOfIterations;如果迭代次数非常大,如何用并行方法完成?答案如下:program loop;{$APPTYPE CONSOLE}const ... 阅读全文