摘要: A void solve() { int n; cin >> n; int cnt = 0; for (int i = 1; i <= n; i++) { int x; cin >> x; if (x == 1) cnt++; } cout << n - cnt << endl; } B 答案可能是 阅读全文
posted @ 2024-02-27 15:13 0x3ea 阅读(6) 评论(0) 推荐(0) 编辑