摘要: A void solve() { vector<int> pr; vector<bool> not_pr(N); auto getpr = [&](int n) { for (int i = 2; i <= n; ++i) { if (!not_pr[i]) pr.push_back(i); for 阅读全文
posted @ 2024-02-26 22:18 0x3ea 阅读(3) 评论(0) 推荐(0) 编辑