Nepctf2023 Review 出题思路及WP

原设计图

Flag格式

NepCTF{%s}

逻辑复原

main

UPX拆壳,main函数逻辑复原得到

  • getInput
  • checkInputFormat
  • debuggerCheck
    • 如果存在,则加密一些数据
  • cotIsDebuggerPresent++
  • checkCRC
  • checkBreakPoint1
  • checkBreakPoint2
  • thread3
  • FinalCheck

checkCRC

  • CRCcheck
  • cotCRCcheck++
  • create CRC thread
    • function: checkCRC

checkBreakPoint1

  • BreakPoint则cotBreakPoint++
  • 其它的则不管

checkBreakPoint2

  • 检测cotBreakPoint个数,判断是否失败

thread3

  • checkCRC
  • keyTEA
keyTEA[0] = 0x19 * cotIsDebuggerPresent;
keyTEA[1] = 0x28 * cotBreakPoint1;
keyTEA[2] = 0x37 * cotCRCcheck;
keyTEA[3] = cotIsDebuggerPresent + cotCRCcheck + cotBreakPoint1
  • xxTEA加密,分析密钥结构可以知道是keyTEA
    • xxTEA可以看加密结构判断,TEA族加密可以通过魔数看出
  • cotSame = flag经过xxTEA后得到的字符串中,相邻且相同的字符个数
  • BitInvert
  • keyAES
keyAES->m128i_i8[0] = 0x19 * cotIsDebuggerPresent;
keyAES->m128i_i8[1] = 5 * cotBreakPoint1 * 8;
keyAES->m128i_i8[2] = 0x37 * cotCRCcheck;
keyAES->m128i_i8[3] = cotSame + cotIsDebuggerPresent + cotBreakPoint1 + cotCRCcheck;
keyAES->m128i_i8[4] = 0x19 * cotIsDebuggerPresent;
keyAES->m128i_i8[5] = 5 * cotBreakPoint1 * 8;
keyAES->m128i_i8[6] = 0x37 * cotCRCcheck;
keyAES->m128i_i8[7] = cotIsDebuggerPresent + cotBreakPoint1 + cotCRCcheck - cotSame;
keyAES->m128i_i8[8] = 70 * cotIsDebuggerPresent;
keyAES->m128i_i8[9] = 85 * cotBreakPoint1;
keyAES->m128i_i8[10] = 100 * cotCRCcheck;
keyAES->m128i_i8[11] = cotSame + cotIsDebuggerPresent + cotBreakPoint1 + cotCRCcheck;
keyAES->m128i_i8[12] = 70 * cotIsDebuggerPresent;
keyAES->m128i_i8[13] = 85 * cotBreakPoint1;
keyAES->m128i_i8[14] = 100 * cotCRCcheck;
keyAES->m128i_i8[15] = cotIsDebuggerPresent + cotBreakPoint1 + cotCRCcheck - cotSame;

  • AES
  • checkCRC

FinalCheck

  • 检查加密后的数据和cmpVal是否相同
  • 不同的话触发异常处理,要求输入不需要的password并且不可能正确

WP

只有cotSame是不确定的值,范围是0~47,后面爆破即可
cotXXX全部都是固定的,只有动态调试的时候会因为触发检测而错误,静态分析显然可以得到不同时刻的状态表

int main() {
    unsigned char flag[SIZE + 1] = "NepCTF{tEA_with_AES_by_mixing_antiDebug_hahaHah}";
    unsigned char comp[SIZE + 1] = { 0 };
    data.cot_Anti1 += 1;
    data.cot_Anti3 += 1;
    data.cot_Anti3 += 1;
    unsigned int keyTEA[4];
    keyTEA[0] = data.cot_Anti1 * 0x19;
    keyTEA[1] = data.cot_Anti2 * 0x28;
    keyTEA[2] = data.cot_Anti3 * 0x37;
    keyTEA[3] = data.cot_Anti1 + data.cot_Anti2 + data.cot_Anti3;
    xxtea_uint_encrypt((unsigned int*)flag, SIZE/4, (unsigned int*)keyTEA);
    data.cot_same = 0;
    data.cot_Anti2 += 1;
    for (int i = 0; i < SIZE; i++) {
        flag[i] = ~flag[i];
    }
    unsigned char* keyAES = new unsigned char[16];
    keyAES[0] = data.cot_Anti1 * 0x19;
    keyAES[1] = data.cot_Anti2 * 0x28;
    keyAES[2] = data.cot_Anti3 * 0x37;
    keyAES[3] = data.cot_Anti1 + data.cot_Anti2 + data.cot_Anti3 + data.cot_same;
    keyAES[4] = data.cot_Anti1 * 0x19;
    keyAES[5] = data.cot_Anti2 * 0x28;
    keyAES[6] = data.cot_Anti3 * 0x37;
    keyAES[7] = data.cot_Anti1 + data.cot_Anti2 + data.cot_Anti3 - data.cot_same;
    keyAES[8] = data.cot_Anti1 * 0x46;
    keyAES[9] = data.cot_Anti2 * 0x55;
    keyAES[10] = data.cot_Anti3 * 0x64;
    keyAES[11] = data.cot_Anti1 + data.cot_Anti2 + data.cot_Anti3 + data.cot_same;
    keyAES[12] = data.cot_Anti1 * 0x46;
    keyAES[13] = data.cot_Anti2 * 0x55;
    keyAES[14] = data.cot_Anti3 * 0x64;
    keyAES[15] = data.cot_Anti1 + data.cot_Anti2 + data.cot_Anti3 - data.cot_same;
    //for (int i = 0; i < 16; i++)
    //   printf("%hx", keyAES[i]);
    aesEncrypt((const unsigned char*)keyAES, 16, (const unsigned char*)flag, (unsigned char*)comp, SIZE);
    data.cot_Anti3 += 1;
    for (int i = 0; i < SIZE; i++)
        printf("%#hx, ", comp[i]);
    return 0;
}
int main() {
	for (int i = 0; i < 48; i++) {
		unsigned char flag[SIZE + 1] = { 0xf4, 0x9c, 0xdd, 0x41, 0x3, 0xdd, 0x5a, 0x13, 0x2e, 0x55, 0x97, 0x9e, 0xff, 0xd5, 0x8, 0xd9, 0xf6, 0xd1, 0x9, 0x8c, 0x68, 0x9e, 0x92, 0xff, 0x75, 0xf, 0x80, 0x95, 0x4b, 0x16, 0xb9, 0xc6, 0x7f, 0x54, 0x2e, 0x20, 0x35, 0xfc, 0x1b, 0x46, 0x14, 0xaa, 0xda, 0x5e, 0x4f, 0xbd, 0x59, 0x71 , 0 };
		unsigned char comp[SIZE + 1] = { 0 };
		data.cot_Anti1 = 1;
		data.cot_Anti2 = 1;
		data.cot_Anti3 = 2;
		data.cot_same = i;
		unsigned char* keyAES = new unsigned char[16];
		keyAES[0] = data.cot_Anti1 * 0x19;
		keyAES[1] = data.cot_Anti2 * 0x28;
		keyAES[2] = data.cot_Anti3 * 0x37;
		keyAES[3] = data.cot_Anti1 + data.cot_Anti2 + data.cot_Anti3 + data.cot_same;
		keyAES[4] = data.cot_Anti1 * 0x19;
		keyAES[5] = data.cot_Anti2 * 0x28;
		keyAES[6] = data.cot_Anti3 * 0x37;
		keyAES[7] = data.cot_Anti1 + data.cot_Anti2 + data.cot_Anti3 - data.cot_same;
		keyAES[8] = data.cot_Anti1 * 0x46;
		keyAES[9] = data.cot_Anti2 * 0x55;
		keyAES[10] = data.cot_Anti3 * 0x64;
		keyAES[11] = data.cot_Anti1 + data.cot_Anti2 + data.cot_Anti3 + data.cot_same;
		keyAES[12] = data.cot_Anti1 * 0x46;
		keyAES[13] = data.cot_Anti2 * 0x55;
		keyAES[14] = data.cot_Anti3 * 0x64;
		keyAES[15] = data.cot_Anti1 + data.cot_Anti2 + data.cot_Anti3 - data.cot_same;
		aesDecrypt((const unsigned char*)keyAES, 16, (const unsigned char*)flag, (unsigned char*)comp, SIZE);
		for (int i = 0; i < SIZE; i++) {
			comp[i] = ~comp[i];
		}
		data.cot_Anti2 = 0;
		unsigned int keyTEA[4];
		keyTEA[0] = data.cot_Anti1 * 0x19;
		keyTEA[1] = data.cot_Anti2 * 0x28;
		keyTEA[2] = data.cot_Anti3 * 0x37;
		keyTEA[3] = data.cot_Anti1 + data.cot_Anti2 + data.cot_Anti3;
		xxtea_uint_decrypt((unsigned int*)comp, SIZE / 4, (unsigned int*)keyTEA);
		for (int i = 0; i < SIZE; i++)
			printf("%c", comp[i]);
		printf("\n");
	}
	return 0;
}

经测试,仅有cot_same==0时有合法flag

NepCTF{tEA_with_AES_by_mixing_antiDebug_hahaHah}
posted @ 2023-08-13 19:12  Carykd  阅读(394)  评论(0编辑  收藏  举报