Cantredo

摘要： Tr A Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 7631 Accepted Submission(s): 5575 Problem D 阅读全文

摘要： B. Jzzhu and Sequences time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Jzzhu has invented 阅读全文

摘要： 1113 矩阵快速幂 1. 3 秒 2. 131,072 KB 3. 40 分 4. "4 级题" 给出一个N N的矩阵，其中的元素均为正整数。求这个矩阵的M次方。由于M次方的计算结果太大，只需要输出每个元素Mod (10^9 + 7）的结果。 输入 第1行：2个数N和M，中间用空格分隔。N为矩阵的 阅读全文

摘要： ACboy needs your help again! Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 11902 Accepted Subm 阅读全文

摘要： 每种面值的货币要多少 Time Limit: 1000 MS Memory Limit: 65536 K Total Submit: 596(357 users) Total Accepted: 370(335 users) Rating: Special Judge: No Description 阅读全文

摘要： Doubles Time Limit: 2 Seconds Memory Limit: 65536 KB As part of an arithmetic competency program, your students will be given randomly generated lists 阅读全文

摘要： Dancing Stars on Me Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 262144/262144 K (Java/Others) Total Submission(s): 2827 Accepted Submission(s 阅读全文

摘要： A. Bicycle Chain time limit per test 2 seconds time limit per test 1 second memory limit per test 256 megabytes input:standard input output:standard o 阅读全文

摘要： 1137 矩阵乘法 给出2个N N的矩阵M1和M2，输出2个矩阵相乘后的结果。 输入 第1行：1个数N，表示矩阵的大小(2 include include include include include using namespace std ; int a[1005][1005] ; int b[ 阅读全文

摘要： 赛题分析 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 512000/512000 K (Java/Others) Total Submission(s): 862 Accepted Submission(s): 503 Problem D 阅读全文