【牛客网-名企高频面试题】 NC45 实现二叉树先序,中序和后序遍历

NC45 实现二叉树先序,中序和后序遍历

题目描述

分别按照二叉树先序,中序和后序

输入:

{1,2,3}

返回值

[[1,2,3],[2,1,3],[2,3,1]]

import java.util.*;

/*
 * public class TreeNode {
 *   int val = 0;
 *   TreeNode left = null;
 *   TreeNode right = null;
 * }
 */

public class Solution {
    /**
     * 
     * @param root TreeNode类 the root of binary tree
     * @return int整型二维数组
     */
    List<Integer> front = new ArrayList<>();
    List<Integer> mid = new ArrayList<>();
    List<Integer> back = new ArrayList<>();
    
    public int[][] threeOrders (TreeNode root) {
        // write code here
        PreOrderTraversal(root);
        InOrderTraversal(root);
        PostOrderTraversal(root);
        
        int[][] res = {
            front.stream().mapToInt(Integer::valueOf).toArray(),
            mid.stream().mapToInt(Integer::valueOf).toArray(),
            back.stream().mapToInt(Integer::valueOf).toArray()
        };
        return res;
    }
    
    //前序遍历
    public void PreOrderTraversal(TreeNode root){
        if(root == null) return;
        front.add(root.val);
        PreOrderTraversal(root.left);
        PreOrderTraversal(root.right);
    }
    //中序遍历
    public void InOrderTraversal(TreeNode root){
        if(root == null) return;
        InOrderTraversal(root.left);
        mid.add(root.val);
        InOrderTraversal(root.right);
    }
    //后序遍历
    public void PostOrderTraversal(TreeNode root){
        if(root == null)
            return;
        PostOrderTraversal(root.left);
        PostOrderTraversal(root.right);
        back.add(root.val);
    }


}
posted @ 2020-12-22 21:05  your_棒棒糖  阅读(64)  评论(0编辑  收藏  举报