dp[i] 表示以第i块木块放在最顶端得到的最高高度
dp[i] = max{dp[i] , dp[j]+block[i].h} j<i
1 #include <cstdio> 2 #include <cstring> 3 #include <algorithm> 4 #include <iostream> 5 using namespace std; 6 #define N 1000 7 struct Block{ 8 int x , y , h; 9 }; 10 11 bool cmp(const Block &a,const Block &b){ 12 if(a.x>b.x) return true; 13 if(a.x==b.x&&a.y>b.y) return true; 14 return false; 15 } 16 17 int k , dp[N]; 18 Block block[N]; 19 20 int main() 21 { 22 // freopen("a.in" , "r" , stdin); 23 int cas = 0; 24 int n , a , b , h; 25 while(~scanf("%d" , &n)){ 26 if(n == 0) break; 27 k = 0; 28 memset(dp,0,sizeof(dp)); 29 for(int i = 0 ; i < n ; i++){ 30 scanf("%d%d%d" , &a , &b , &h); 31 block[k].x = a , block[k].y = b , block[k++].h = h; 32 block[k].x = b , block[k].y = a , block[k++].h = h; 33 block[k].x = a , block[k].y = h , block[k++].h = b; 34 block[k].x = h , block[k].y = a , block[k++].h = b; 35 block[k].x = b , block[k].y = h , block[k++].h = a; 36 block[k].x = h , block[k].y = b , block[k++].h = a; 37 } 38 39 sort(block , block+k , cmp); 40 41 for(int i = 0 ; i<k ; i++){ 42 dp[i] = block[i].h; 43 for(int j = 0 ; j<=i ; j++){ 44 if(block[i].x < block[j].x && block[i].y < block[j].y){ 45 dp[i] = max(dp[i] , dp[j] + block[i].h); 46 } 47 } 48 } 49 50 int maxn = 0; 51 for(int i = 0 ; i<k ; i++) 52 maxn = max(maxn , dp[i]); 53 printf("Case %d: maximum height = %d\n" , ++cas , maxn); 54 } 55 return 0; 56 }
我还在坚持,我还未达到我所想,梦~~一直在