MSSQL 获取递归树形表数据

1.根据节点主键,查询当前节点和所有子节点

WITH SOURCE AS (
  SELECT * FROM TableName WHERE DeleteState = 0
),
LIST AS (
  SELECT value FROM STRING_SPLIT('2111011043240001', ',')
),
RESULT AS (
  SELECT SOURCE.* FROM SOURCE 
  INNER JOIN LIST ON SOURCE.Code = LIST.value
  UNION ALL
  SELECT SOURCE.* FROM RESULT 
    INNER JOIN SOURCE ON RESULT.Code = SOURCE.ParentCode
)

SELECT Code, ParentCode, NodeName, NodeIndex, IsLastNode FROM RESULT

2.根据节点主键,查询当前节点和所有父节点

WITH SOURCE AS (
  SELECT * FROM TableName WHERE DeleteState = 0
),
LIST AS (
  SELECT value FROM STRING_SPLIT('2111011043260028', ',')
),
RESULT AS (
  SELECT SOURCE.* FROM SOURCE 
  INNER JOIN LIST ON SOURCE.Code = LIST.value
  UNION ALL
  SELECT SOURCE.* FROM RESULT 
    INNER JOIN SOURCE ON RESULT.ParentCode = SOURCE.Code
)
SELECT Code, ParentCode, NodeName, NodeIndex, IsLastNode FROM RESULT

 

posted @ 2021-11-03 15:25  Robot-Blog  阅读(189)  评论(0编辑  收藏  举报