Codeforces 1089D Eels (看题解)
感觉想不出来这种东西。。 题解讲的很清楚啦。 我好lj啊。
https://codeforces.com/blog/entry/64331
#include<bits/stdc++.h> #define LL long long #define LD long double #define ull unsigned long long #define fi first #define se second #define mk make_pair #define PLL pair<LL, LL> #define PLI pair<LL, int> #define PII pair<int, int> #define SZ(x) ((int)x.size()) #define ALL(x) (x).begin(), (x).end() #define fio ios::sync_with_stdio(false); cin.tie(0); using namespace std; const int N = 5e5 + 7; const int inf = 0x3f3f3f3f; const LL INF = 0x3f3f3f3f3f3f3f3f; const int mod = 998244353; const double eps = 1e-8; const double PI = acos(-1); template<class T, class S> inline void add(T& a, S b) {a += b; if(a >= mod) a -= mod;} template<class T, class S> inline void sub(T& a, S b) {a -= b; if(a < 0) a += mod;} template<class T, class S> inline bool chkmax(T& a, S b) {return a < b ? a = b, true : false;} template<class T, class S> inline bool chkmin(T& a, S b) {return a > b ? a = b, true : false;} int q, x, n; char op[3]; multiset<int> Set[31]; int mn[31][2]; LL sum[31]; void Add(int x) { int p = 0; while((1 << p) <= x) p++; Set[p].insert(x); sum[p] += x; n++; auto it = Set[p].begin(); mn[p][0] = *it; if(SZ(Set[p]) > 1) ++it, mn[p][1] = *it; } void Del(int x) { int p = 0; while((1 << p) <= x) p++; Set[p].erase(Set[p].lower_bound(x)); sum[p] -= x; n--; auto it = Set[p].begin(); if(SZ(Set[p]) > 0) mn[p][0] = *it; if(SZ(Set[p]) > 1) ++it, mn[p][1] = *it; } int calc() { if(!n) return 0; LL prefix = 0; int ret = 0; for(int i = 1; i < 31; i++) { if(!SZ(Set[i])) continue; LL nprefix = prefix + sum[i]; for(int j = 0; j < min(2, SZ(Set[i])); j++) { if(prefix && 2 * prefix < mn[i][j]) { ret++; break; } prefix += mn[i][j]; } prefix = nprefix; } return n - ret - 1; } int main() { scanf("%d", &q); while(q--) { scanf("%s%d", op, &x); if(*op == '+') Add(x); else Del(x); printf("%d\n", calc()); } return 0; } /* */