摘要: function simplifyNum(number) { if (!number && number != 0) return number; var str_num if (number >= 1E3 && number < 1E4) { str_num = number / 1E3 retu 阅读全文
posted @ 2022-08-05 11:30 abcByme 阅读(1321) 评论(0) 推荐(0) 编辑