【杭电】[1242]Rescue

虽然学长把这题取名为BFS……
不过一时脑抽没分清BFS是深搜还是广搜
所以用的DFS做的

不过对于这种水题其实都一样啦
没什么坑点
用一个二维数组保存每个点到终点的距离
然后递归搜索
遇见x就+2
遇见.就+1

#include<stdio.h>
int inf=9999999;
char map[220][220];
int dis[220][220];
int n,m;
int mn,mm;
int en,em;
void bfs(int tn,int tm) {
    if(tm+1<m&&((map[tn][tm+1]=='.'&&dis[tn][tm+1]>=dis[tn][tm]+1)||(map[tn][tm+1]=='x'&&dis[tn][tm+1]>=dis[tn][tm]+2))) {
        dis[tn][tm+1]=dis[tn][tm]+1;
        if(map[tn][tm+1]=='x')
            dis[tn][tm+1]++;
        bfs(tn,tm+1);
    }
    if(tm-1>=0&&((map[tn][tm-1]=='.'&&dis[tn][tm-1]>=dis[tn][tm]+1)||(map[tn][tm-1]=='x'&&dis[tn][tm-1]>=dis[tn][tm]+2))) {
        dis[tn][tm-1]=dis[tn][tm]+1;
        if(map[tn][tm-1]=='x')
            dis[tn][tm-1]++;
        bfs(tn,tm-1);
    }
    if(tn-1>=0&&((map[tn-1][tm]=='.'&&dis[tn-1][tm]>=dis[tn][tm]+1)||(map[tn-1][tm]=='x'&&dis[tn-1][tm]>=dis[tn][tm]+2))) {
        dis[tn-1][tm]=dis[tn][tm]+1;
        if(map[tn-1][tm]=='x')
            dis[tn-1][tm]++;
        bfs(tn-1,tm);
    }
    if(tn+1<n&&((map[tn+1][tm]=='.'&&dis[tn+1][tm]>=dis[tn][tm]+1)||(map[tn+1][tm]=='x'&&dis[tn+1][tm]>=dis[tn][tm]+2))) {
        dis[tn+1][tm]=dis[tn][tm]+1;
        if(map[tn+1][tm]=='x')
            dis[tn+1][tm]++;
        bfs(tn+1,tm);
    }
}
int main() {
    while(scanf("%d %d",&n,&m)!=EOF) {
        getchar();
        for(int i=0; i<n; i++) {
            for(int j=0; j<m; j++) {
                dis[i][j]=inf;
                scanf("%c",&map[i][j]);
                if(map[i][j]=='r') {
                    mn=i;
                    mm=j;
                    dis[i][j]=0;
                } else if(map[i][j]=='a') {
                    en=i;
                    em=j;
                    map[i][j]='.';
                }
            }
            getchar();
        }
        bfs(mn,mm);
        if(dis[en][em]==inf)
            printf("Poor ANGEL has to stay in the prison all his life.\n");
        else
            printf("%d\n",dis[en][em]);
    }
    return 0;
}

题目记录:【杭电】[1242]Rescue