PAT 1036 Boys vs Girls[简单]
1036 Boys vs Girls (25 分)
This time you are asked to tell the difference between the lowest grade of all the male students and the highest grade of all the female students.
Input Specification:
Each input file contains one test case. Each case contains a positive integer N, followed by N lines of student information. Each line contains a student's name
, gender
, ID
and grade
, separated by a space, where name
and ID
are strings of no more than 10 characters with no space, gender
is either F
(female) or M
(male), and grade
is an integer between 0 and 100. It is guaranteed that all the grades are distinct.
Output Specification:
For each test case, output in 3 lines. The first line gives the name and ID of the female student with the highest grade, and the second line gives that of the male student with the lowest grade. The third line gives the difference gradeF−gradeM. If one such kind of student is missing, output Absent
in the corresponding line, and output NA
in the third line instead.
Sample Input 1:
3
Joe M Math990112 89
Mike M CS991301 100
Mary F EE990830 95
Sample Output 1:
Mary EE990830
Joe Math990112
6
Sample Input 2:
1
Jean M AA980920 60
Sample Output 2:
Absent
Jean AA980920
NA
题目大意:给出m个女孩和男孩的名字课程分数信息,求女孩中分数最高与男孩中分数最低的。
//这道题真的老简单了。。。一次过。。都不想写博客来着。。
#include <iostream> #include <algorithm> #include <vector> #include<cstdio> using namespace std; int main() { int n; cin>>n; string name,s,task; int sco; string fn,mn;//最终的名字 string ft,mt;//最终的科目 int fs=-1,ms=101;//最终的得分。 for(int i=0;i<n;i++){ cin>>name>>s>>task>>sco; if(s=="F"&&sco>fs){ fn=name; ft=task; fs=sco; }else if(s=="M"&&sco<ms){ mn=name; mt=task; ms=sco; } } if(fs==-1){//如果没有女性 cout<<"Absent\n"; }else { cout<<fn<<" "<<ft<<"\n"; } if(ms==101){ cout<<"Absent\n"; }else{ cout<<mn<<" "<<mt<<"\n"; } if(fs==-1||ms==101){ cout<<"NA"; }else{ cout<<fs-ms; } return 0; }