POJ1426——Find The Multiple

POJ1426——Find The Multiple

Description

Given a positive integer n, write a program to find out a nonzero multiple m of n whose decimal representation contains only the digits 0 and 1. You may assume that n is not greater than 200 and there is a corresponding m containing no more than 100 decimal digits.

Input

The input file may contain multiple test cases. Each line contains a value of n (1 <= n <= 200). A line containing a zero terminates the input.

Output

For each value of n in the input print a line containing the corresponding value of m. The decimal representation of m must not contain more than 100 digits. If there are multiple solutions for a given value of n, any one of them is acceptable.

Sample Input

2
6
19
0

Sample Output

10
100100100100100100
111111111111111111

 

代码:

#include<iostream>
#include<bits/stdc++.h>
#include<queue>
using namespace std;

void BFS(int x){
    queue<int> q ;
    q.push(1);
    int y;
    while (!q.empty())
    {
        y=q.front();
        q.pop();
        for (int i = 0; i < 2; i++)
        {
            if (i==0) q.push(y*10);
            else 
                q.push(y*10+1);
            if (y%x==0)
            {
                cout<<y<<endl;
                return ;
            }
            
        }
    }
}

int main(){
    int x;
    while ((cin>>x)&&x)
    {
       BFS(x);
    }
}

 

posted @ 2020-09-21 09:09  图神经网络  阅读(98)  评论(0编辑  收藏  举报
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