181超过经理收入的员工

181 工资超过经理的员工

表：Employee

+-------------+---------+
| Column Name | Type    |
+-------------+---------+
| id          | int     |
| name        | varchar |
| salary      | int     |
| managerId   | int     |
+-------------+---------+
id 是该表的主键（具有唯一值的列）。
该表的每一行都表示雇员的ID、姓名、工资和经理的ID。

编写解决方案，找出收入比经理高的员工。

以 任意顺序 返回结果表。

结果格式如下所示。

示例 1:

<strong>输入:</strong> 
Employee 表:
+----+-------+--------+-----------+
| id | name  | salary | managerId |
+----+-------+--------+-----------+
| 1  | Joe   | 70000  | 3         |
| 2  | Henry | 80000  | 4         |
| 3  | Sam   | 60000  | Null      |
| 4  | Max   | 90000  | Null      |
+----+-------+--------+-----------+
<strong>输出:</strong> 
+----------+
| Employee |
+----------+
| Joe      |
+----------+
<strong>解释:</strong> Joe 是唯一挣得比经理多的雇员。

-- 创建表
create table Employee (
	id  int IDENTITY(1,1) primary key,
	name varchar(50),
	salary int,
	managerId int
)
go
--插入数据
insert into Employee values('Joe','7000',3);
insert into Employee values('Henry','8000',4);
insert into Employee values('Sam','6000',null);
insert into Employee values('Max','9000',null);

--解题 ms sql server
select temp.name Employee  
from  
(
select e1.name,e1.salary e1_s,e2.salary m_s 
from Employee e1 
inner join 
Employee e2 
on e1.managerId=e2.id
) as  temp
 where temp.e1_s>temp.m_s