报错Unable to sendViaPost to url、invalid query

String cfgItem = "检查状态信息更新服务";
cfgItem = URLEncoder.encode(cfgItem, "UTF-8");// 中文转码
String urlString = "http://132.166.254.50:80/soap/JHIPLIB.SOAP.BS.HL7V3Service.cls?CfgItem=JH0405"+cfgItem;

posted @ 2022-12-26 12:05  894316728  阅读(449)  评论(0编辑  收藏  举报