Problem C: 平面上的点和线——Point类、Line类 (III)

Problem C: 平面上的点和线——Point类、Line类 (III)

Time Limit: 1 Sec  Memory Limit: 128 MB
Submit: 9040  Solved: 4462
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Description

在数学上，平面直角坐标系上的点用X轴和Y轴上的两个坐标值唯一确定，两点确定一条线段。现在我们封装一个“Point类”和“Line类”来实现平面上的点的操作。

 

根据“append.cc”，完成Point类和Line类的构造方法和show()方法，输出各Line对象和Point对象的构造和析构次序。

 

接口描述：

Point::show()方法：按格式输出Point对象。

Line::show()方法：按格式输出Line对象。

 

 

Input

输入的第一行为N，表示后面有N行测试样例。每行为两组坐标“x,y”，分别表示线段起点和终点的x坐标和y坐标，两组坐标间用一个空格分开，x和y的值都在double数据范围内。

 

Output

输出为多行，每行为一条线段，起点坐标在前终点坐标在后，每个点的X坐标在前，Y坐标在后，Y坐标前面多输出一个空格，用括号包裹起来。输出格式见sample。

 

C语言的输入输出被禁用。

 

Sample Input

4 0,0 1,1 1,1 2,3 2,3 4,5 0,1 1,0

Sample Output

Point : (1, -2) is created. Point : (2, -1) is created. Point : (0, 0) is created. Point : (0, 0) ========================= Point : (0, 0) is created. Point : (1, 1) is created. Line : (0, 0) to (1, 1) is created. Line : (0, 0) to (1, 1) Line : (0, 0) to (1, 1) is erased. Point : (1, 1) is erased. Point : (0, 0) is erased. ========================= Point : (1, 1) is created. Point : (2, 3) is created. Line : (1, 1) to (2, 3) is created. Line : (1, 1) to (2, 3) Line : (1, 1) to (2, 3) is erased. Point : (2, 3) is erased. Point : (1, 1) is erased. ========================= Point : (2, 3) is created. Point : (4, 5) is created. Line : (2, 3) to (4, 5) is created. Line : (2, 3) to (4, 5) Line : (2, 3) to (4, 5) is erased. Point : (4, 5) is erased. Point : (2, 3) is erased. ========================= Point : (0, 1) is created. Point : (1, 0) is created. Line : (0, 1) to (1, 0) is created. Line : (0, 1) to (1, 0) Line : (0, 1) to (1, 0) is erased. Point : (1, 0) is erased. Point : (0, 1) is erased. ========================= Point : (1, -2) is copied. Point : (2, -1) is copied. Line : (1, -2) to (2, -1) is created. Point : (1, -2) is copied. Point : (0, 0) is copied. Line : (1, -2) to (0, 0) is created. Point : (2, -1) is copied. Point : (0, 0) is copied. Line : (2, -1) to (0, 0) is created. Point : (0, 0) is copied. Point : (2, -1) is copied. Line : (0, 0) to (2, -1) is created. Line : (1, -2) to (2, -1) Line : (1, -2) to (0, 0) Line : (2, -1) to (0, 0) Line : (0, 0) to (2, -1) Line : (0, 0) to (2, -1) is erased. Point : (2, -1) is erased. Point : (0, 0) is erased. Line : (2, -1) to (0, 0) is erased. Point : (0, 0) is erased. Point : (2, -1) is erased. Line : (1, -2) to (0, 0) is erased. Point : (0, 0) is erased. Point : (1, -2) is erased. Line : (1, -2) to (2, -1) is erased. Point : (2, -1) is erased. Point : (1, -2) is erased. Point : (0, 0) is erased. Point : (2, -1) is erased. Point : (1, -2) is erased.

#include <iostream>
using namespace std;
class Point
{
private:
    double st,ed;
public:
    Point():st(0),ed(0){cout << "Point : (" <<st<< ", " <<ed<<") is created." << endl;}
    Point(double stt ,double edd ):st(stt),ed(edd){cout << "Point : (" <<st<< ", " <<ed<<") is created." << endl;}
    Point (const Point &p)
 {st = p.st;ed= p.ed;cout << "Point : (" << st<< ", " << ed<<") is copied." << endl;}
    double x() const {return st;}
    double y() const {return ed;}
    void show()
    {
        cout << "Point : (" <<st<< ", "<<ed<< ")" <<endl;
    }
    ~Point ()
  {
      cout << "Point : (" <<st<< ", " <<ed <<") is erased." << endl;
  }
};
class Line
{
private :
    Point st_,ed_;
public:
  Line( Point &sst, Point &eed):st_(sst),ed_(eed)
    { cout << "Line : (" << st_.x() << ", " << st_.y()<< ") to (" <<ed_.x() <<", " << ed_.y() << ")" << " is created." << endl;}
    Line(double x1,double y1,double x2,double y2):st_(x1,y1),ed_(x2,y2)
    {
   cout << "Line : (" << st_.x() << ", " << st_.y()<< ") to (" <<ed_.x() <<", " << ed_.y() << ")" << " is created." << endl;
    }
    void show() const
    {cout << "Line : (" << st_.x() << ", " << st_.y()<< ") to (" <<ed_.x() <<", " << ed_.y() << ")" <<endl;
    }
    ~Line()
    {
       cout << "Line : (" << st_.x() << ", " << st_.y()<< ") to (" <<ed_.x() <<", " << ed_.y() << ")" << " is erased." << endl;
    }
};
int main()
{
    char c;
    int num, i;
    double x1, x2, y1, y2;
    Point p(1, -2), q(2, -1), t;
    t.show();
    std::cin>>num;
    for(i = 1; i <= num; i++)
    {
        std::cout<<"=========================\n";
        std::cin>>x1>>c>>y1>>x2>>c>>y2;
        Line line(x1, y1, x2, y2);
        line.show();
    }
    std::cout<<"=========================\n";
    Line l1(p, q), l2(p, t), l3(q, t), l4(t, q);
    l1.show();
    l2.show();
    l3.show();
    l4.show();
}