Problem C: 平面上的点——Point类 (III)
Problem C: 平面上的点——Point类 (III)
Time Limit: 1 Sec Memory Limit: 4 MBSubmit: 7954 Solved: 5141
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Description
在数学上,平面直角坐标系上的点用X轴和Y轴上的两个坐标值唯一确定。现在我们封装一个“Point类”来实现平面上的点的操作。
根据“append.cc”,完成Point类的构造方法和show()方法,输出各Point对象的构造和析构次序。实现showPoint()函数。
接口描述:
showPoint()函数按输出格式输出Point对象,调用Point::show()方法实现。
Point::show()方法:按输出格式输出Point对象。
Input
输入多行,每行为一组坐标“x,y”,表示点的x坐标和y坐标,x和y的值都在double数据范围内。
Output
输出每个Point对象的构造和析构行为。showPoint()函数用来输出(通过参数传入的)Point对象的值:X坐标在前,Y坐标在后,Y坐标前面多输出一个空格。每个坐标的输出精度为最长16位。输出格式见sample。
C语言的输入输出被禁用。
Sample Input
1,2
3,3
2,1
Sample Output
Point : (0, 0) is created.
Point : (1, 2) is created.
Point : (1, 2) is copied.
Point : (1, 2)
Point : (1, 2) is erased.
Point : (1, 2) is erased.
Point : (3, 3) is created.
Point : (3, 3) is copied.
Point : (3, 3)
Point : (3, 3) is erased.
Point : (3, 3) is erased.
Point : (2, 1) is created.
Point : (2, 1) is copied.
Point : (2, 1)
Point : (2, 1) is erased.
Point : (2, 1) is erased.
Point : (0, 0) is copied.
Point : (1, 1) is created.
Point : (0, 0) is copied.
Point : (1, 1) is copied.
Point : (0, 0) is copied.
Point : (0, 0)
Point : (1, 1)
Point : (0, 0)
Point : (0, 0) is erased.
Point : (1, 1) is erased.
Point : (0, 0) is erased.
Point : (1, 1) is erased.
Point : (0, 0) is erased.
Point : (0, 0) is erased.
#include <iostream> #include <iomanip> using namespace std; class Point { double x; double y; public: Point():x(0),y(0) { cout<<setprecision(16)<<"Point : ("<<x<<", "<<y<<") is created."<<endl; } Point(double a,double b):x(a),y(b) { cout<<setprecision(16)<<"Point : ("<<x<<", "<<y<<") is created."<<endl; } Point(double a):x(a),y(1) { cout <<setprecision(16)<<"Point : ("<<x<<", "<<y<<")"<<" is created."<<endl; } Point(const Point& p) { x=p.x; y=p.y; cout <<setprecision(16)<<"Point : ("<<p.x<<", "<<p.y<<")"<<" is copied."<<endl; } ~Point() { cout<<setprecision(16)<<"Point : ("<<x<<", "<<y<<") is erased."<<endl; } void show() { cout<<setprecision(16)<<"Point : ("<<x<<", "<<y<<")"<<endl; } }; void showPoint(Point p) { p.show(); } void showPoint(Point p1, Point p2, Point p3) { p1.show(); p2.show(); p3.show(); } int main() { char c; double a, b; Point q; while(std::cin>>a>>c>>b) { Point p(a, b); showPoint(p); } Point q1(q), q2(1); showPoint(q1, q2, q); }