DASCTF 2024暑期挑战赛 RE

DASCTF 2024暑期挑战赛

DosSnake

使用ghidra看反汇编

发现有XOR操作

在ida里面看汇编跟一下

字符DASCTF地址往下6个存放的数据与DASCTF字符串进行异或

A=[0x3f,0x09,0x63,0x34,0x32,0x13,0x2a,0x2f,0x2a,0x37,0x3c,0x23,0x00,0x2e,0x20,0x10,0x3a,0x27,0x2f,0x24,0x3a,0x30,0x75,0x67,0x65,0x3c]
B=[ord(i) for i in "DASCTF"]
for i in range(26):
    A[i]=A[i]^B[i%6]
    print(chr(A[i]),end="")
    
#DASCTF{H0wfUnnytheDosSnakeis!!!}

Strangeprograme

可以通过硬件断点来获取HOOK函数

遍历IAT HOOKmemcmp函数

真实逻辑

KEY

#include <stdio.h>
#include <stdint.h>
//解密函数
void decrypt (uint32_t* v, uint32_t* k) {
    uint32_t v0=v[0], v1=v[1], i; 
	uint32_t delta=0x61C88647;  
	uint32_t sum=-delta*0x10;                 
    uint32_t k0=k[0], k1=k[1], k2=k[2], k3=k[3];   /* cache key */
    for (i=0; i<0x10; i++) {                         /* basic cycle start */
        sum += 0x61C88647;
        v1 -= (k3 + (v0 >> 5)) ^ (sum + v0) ^ (k2 + v0 * 16);
        v0 -= (k1 + (v1 >> 5)) ^ (sum + v1) ^ (k0 + v1 * 16);
    }                                              /* end cycle */
    v[0]=v0; v[1]=v1;
}


 int main() {
    uint32_t key[]={ 0x12345678, 0x09101112, 0x13141516, 0x15161718 };
	uint32_t enc[40]={0xBC2B4DF9, 0x6213DD13, 0x89FFFCC9, 0x0FC94F7D, 0x526D1D63, 0xE341FD50, 0x97287633, 0x6BF93638, 
    0x83143990, 0x1F2CE22C};
	for (size_t i = 8; i >= 2; i-=2)
	{
        enc[i] ^= enc[0];
        enc[i+1] ^= enc[1];
		decrypt(enc,key);
	}
    decrypt(enc,key);
	puts((char*)enc);
	
}

#DASCTF{I4TH0ok_I5S0ooFunny_Isnotit?????}

BabyAndroid

给了txt，里面有一些数据，全局搜yuanshen

动态加载dex，使用frida-dexdump

看到加密的逻辑

AES ECB解密

import java.util.Base64;
import javax.crypto.Cipher;
import javax.crypto.spec.SecretKeySpec;

public class Encrypto {
    private static final String KEY = "DSACTF";
    private static final String TAG = "Encrypto";

    private static byte[] customHash(String str) {
        int i;
        byte[] keyBytes = new byte[16];
        int[] temp = new int[16];
        for (i = 0; i < str.length(); i++) {
            char charAt = str.charAt(i);
            for (int i2 = 0; i2 < 16; i2++) {
                temp[i2] = ((temp[i2] * 31) + charAt) % 251;
            }
        }
        for (i = 0; i < 16; i++) {
            keyBytes[i] = (byte) (temp[i] % 256);
        }
        return keyBytes;
    }

    public static String encrypt(String str) throws Exception {
        SecretKeySpec secretKeySpec = new SecretKeySpec(customHash(KEY), "AES");
        Cipher cipher = Cipher.getInstance("AES/ECB/PKCS5Padding");
        cipher.init(Cipher.ENCRYPT_MODE, secretKeySpec);
        return Base64.getEncoder().encodeToString(cipher.doFinal(str.getBytes("UTF-8")));
    }

    public static String decrypt(String encryptedStr) throws Exception {
        SecretKeySpec secretKeySpec = new SecretKeySpec(customHash(KEY), "AES");
        Cipher cipher = Cipher.getInstance("AES/ECB/PKCS5Padding");
        cipher.init(Cipher.DECRYPT_MODE, secretKeySpec);
        byte[] decodedBytes = Base64.getDecoder().decode(encryptedStr);
        byte[] decryptedBytes = cipher.doFinal(decodedBytes);
        return new String(decryptedBytes, "UTF-8");
    }

    public static void main(String[] args) {
        try {

            String encryptedText = "TwMkYUkg4bYsY0hL99ggYWnVjWyXQrWAdNmToB0eBXbS6wBzL6ktorjNWI9VOroTU4HgIUYyzGLpcHzd1zNGT+bFZZI7IoxJwpcgXfdwW1LSmiNSP+PuSUsqAzNclF1nJ07b4tYyLWg0zTypbzWsLhOIM+6uci3RFZLREUCALafi01M8mS+KMNxX1Pyn8mSP+KKKjQ5S5fasHRSn+L9qBFws0mWavpfI0QEiMgarxv0iGhYU8cfgonWyL70RvoXET5VUDP1vfYWIBLzzzaAqLC0OiMtUK3TTATSU7yijdgXm18OKMcGIke/NZIM6Sr5fL3t6psDOOkw2C/5uYrJVPn+D6U9KTL64bgREppDqMOvhvbhtuf/S3ASW/+rhtPMtoaD8FxDg0wWSLZA53fQfNA==";

            String decryptedText = Encrypto.decrypt(encryptedText);
            System.out.println("Decrypted Text: " + decryptedText);
        } catch (Exception e) {
            e.printStackTrace();
        }
    }
}
//Decrypted Text: 458.853181,-18.325492,-18.251911,-2.097520,-21.198660,-22.304648,21.103162,-5.786284,-15.248906,15.329286,16.919499,-19.669045,30.928253,-37.588034,-16.593954,-5.505211,3.014744,6.553616,31.131491,16.472500,6.802400,-78.278577,15.280099,3.893073,56.493581,-34.576344,30.146729,4.445671,6.732204

输出是浮点数 调用了native层的sendInit函数

继续跟进解密函数

搜了一下是离散余弦变换

import numpy as np
from scipy.fftpack import dct, idct
A=[458.853181,-18.325492,-18.251911,-2.097520,-21.198660,-22.304648,21.103162,-5.786284,-15.248906,15.329286,16.919499,-19.669045,30.928253,-37.588034,-16.593954,-5.505211,3.014744,6.553616,31.131491,16.472500,6.802400,-78.278577,15.280099,3.893073,56.493581,-34.576344,30.146729,4.445671,6.732204]
#离散余弦变化逆变换 
C = idct(A, norm='ortho')
print(C)
#chr输出 四舍五入
for i in range(len(C)):
    C[i] = round(C[i])
print(''.join([chr(int(i)) for i in C]))

#DASCTF{Y0u_Ar3Re4lly_H@ck3r!}