摘要: <?php $serverName = "192.168.2.251,2434"; $connectionInfo = array( "Database"=>"jfdf40", "UID"=>"sa", "PWD"=>"XXX"); $conn = sqlsrv_connect( $serverNa 阅读全文
posted @ 2022-01-20 14:19 Tag 阅读(153) 评论(0) 推荐(0) 编辑