UVA 1146 Now or later 2-sat
//#pragma comment(linker, "/STACK:1024000000,1024000000") #include<cstdio> #include<cstring> #include<cstdlib> #include<algorithm> #include<iostream> #include<sstream> #include<cmath> #include<climits> #include<string> #include<map> #include<queue> #include<vector> #include<stack> #include<set> using namespace std; typedef long long ll; typedef unsigned long long ull; typedef pair<int,int> pii; #define pb(a) push(a) #define INF 0x1f1f1f1f #define lson idx<<1,l,mid #define rson idx<<1|1,mid+1,r #define PI 3.1415926535898 template<class T> T min(const T& a,const T& b,const T& c) { return min(min(a,b),min(a,c)); } template<class T> T max(const T& a,const T& b,const T& c) { return max(max(a,b),max(a,c)); } void debug() { #ifdef ONLINE_JUDGE #else freopen("d:\\in1.txt","r",stdin); freopen("d:\\out1.txt","w",stdout); #endif } int getch() { int ch; while((ch=getchar())!=EOF) { if(ch!=' '&&ch!='\n')return ch; } return EOF; } struct Edge { int u,v; }; const int maxn=2005; struct TwoSat { vector<int> g[maxn*2]; int mark[maxn*2]; int s[maxn],c; int n; void init(int n) { this->n=n; for(int i=0;i<2*n;i++) g[i].clear(); memset(mark,0,sizeof(mark)); } void add_clause(int x,int xval,int y,int yval) { x=x*2+xval; y=y*2+yval; g[x].push_back(y^1); g[y].push_back(x^1); } bool dfs(int x) { if(mark[x^1])return false; if(mark[x])return true; mark[x]=1; s[c++]=x; for(int i=0;i<g[x].size();i++) { if(!dfs(g[x][i]))return false; } return true; } bool solve() { for(int i=0;i<n;i++) { int a=i*2,b=i*2+1; if(!mark[a]&&!mark[b]) { c=0; if(!dfs(a)) { while(c)mark[s[--c]]=false; if(!dfs(b))return false; } } } return true; } }; TwoSat solver; int T[maxn][2]; int n; void input(int n) { for(int i=0;i<n;i++) for(int a=0;a<2;a++) scanf("%d",&T[i][a]); } bool check(int t) { solver.init(n); for(int i=0;i<n;i++)for(int a=0;a<2;a++) for(int j=i+1;j<n;j++)for(int b=0;b<2;b++) if(abs(T[i][a]-T[j][b])<t) solver.add_clause(i,a,j,b); return solver.solve(); } int main() { while(scanf("%d",&n)!=EOF) { input(n); int l=0,r=10000001; while(l<r) { int mid=l+(r-l)/2; if(check(mid)) l=mid+1; else r=mid; } printf("%d\n",l-1); } return 0; }